Melanie Hollis
October 5, 2011
Assignment 5
2.1
Usefulness of Model (using ANOVA):
Hypothesis:
:
Decision Rule:
Reject
in favor of
if the pvalue is less than 0.05.
Test Statistic:
F===4633.721378
Pvalue: Approximately 0
Conclusion: Reject
in favor of . Model is Useful.
===0.9966
> anova(lm(current~last))
Analysis of Variance Table
Response: current
Df
Sum Sq
Mean Sq F value
Pr(>F)
last
1 1.5026e+12 1.5026e+12
4633.7 < 2.2e16 ***
Residuals 16 5.1884e+09 3.2427e+08

Signif. codes:
0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
2.2
Usefulness of Model (using ANOVA):
Hypothesis:
:
Decision Rule:
Reject
in favor of
if the pvalue is less than 0.05.
Test Statistic:
F===6.19596
Pvalue:0.0242
Conclusion: Reject
in favor of . Model is Useful.
===0.2791
> anova(lm(price~loan))
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Melanie Hollis
October 5, 2011
Analysis of Variance Table
Response: price
Df Sum Sq Mean Sq F value
Pr(>F)
loan
1
96.87
96.870
6.1961 0.02419 *
Residuals 16 250.15
15.634

Signif. codes:
0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
2.3
Usefulness of Model (using ANOVA):
Hypothesis:
:
Decision Rule:
Reject
in favor of
if the pvalue is less than 0.05.
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 Spring '11
 Holt
 Statistics, Normal Distribution, Sum Sq Mean, Df Sum Sq

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