Unformatted text preview: θ to find radial and tangential components of velocity ( ) v and r v . Equate these to corresponding derivatives of the velocity potential . Integrate ∂ ∂ ∂ ∂ and r to get . The answer will be r cos 2 = . 4. Using the MATLAB script given in a recent handout as a starting point, construct contours of the following stream function, which corresponds to the superposition of a uniform flow and a doublet: = ∞ 2 2 1 r R y u You may use any numerical value for the velocity u ∞ and R (Being unimaginative, I would use unity). Visually verify that this represents flow over a circular cylinder of radius R....
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 Fall '08
 Yeung
 Fluid Dynamics, Derivative, Cartesian Coordinate System, velocity potential

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