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Unformatted text preview: ENU 4134 Convection to Coolant Part I D. Schubring Fall 2011 Learning Objectives I 3e Apply knowledge of singlephase and twophase convective heat transfer to convection from fuel rods to coolants, including adjustments to correlations regarded in assembly geometry I 4a Use equations from nuclear heat transfer (as simple functions of axial coordinate z ) to perform simple, analytical singlechannel analysis (SCA) I 4b Derive finite volume method for use in steadystate SCA I 4c Implement finite volume method in scripting or compiled language to solve a wide range of LWR SCA problems (Pr. 2) I 4d Use general SCA code to efficiently perform design/safety analyses for LWR (Pr. 2) I 4e Integrate knowledge from course to evaluate safety and designsignificance of results from SCA code (Pr. 2) + all crosscutting technical objectives (#5) General Equation for T co T m Convective heat transfer is typically understood through the heat transfer coefficient: q 00 co = htc ( T co T m ) (1) T co T m = q 00 co htc = q 2 R co htc (2) Computation of htc can be nontrivial, particularly for the 2phase case, but this equation is general for any htc . Solution of the nuclear TH (singlechannel analysis) problem is greatly aided by the fact that q is usually given. Must consider adjustments to htc due to rod bundle geometry. Example Problem I P = 14.608 MPa I Geometry: P = 12 mm, D =10 mm, R fo = 4.6 mm, R ci = 4.7 mm I htc g = 5000 W m 2 K 1 I Equation for htc (heat transfer coefficient) (Weisman 1 , Schrock and Grossman 2 ) I k c = 20 W m 1 K 1 and k f = 3 W m 1 K 1 I q = 25 kW/m I m = 0 . 15 kg/s (per channel) I T 1 = 320 C , T 2 = T sat = 340 x 2 = 0 . 2 Equations for Solution T co T m = q 2 R co htc (3) T ci T co = q 2 k c ln R co R ci (4) T fo T ci = q 2 R g htc g = q ( R ci + R fo ) htc g (5) T max T fo = q 4 k f (6) This is the end of material in the scope of Exam 2 Single Channel Analysis I Singlephase coolant, constant properties & heat transfer coefficient (analytical solutions) I Singlephase coolant, variable properties & heat transfer coefficient (numerical solution) I Twophase coolant I Miscellanea I Engineering judgment and singlechannel analysis Axial Dependence There are simple(ish) equations for the unknown temperatures. However, many of the variables are actually functions of z (if not also local T s). T co ( z ) T m ( z ) = q ( z ) 2 R co htc ( z ) (7) T ci ( z ) T co ( z ) = q ( z ) 2 k c ( z ) ln R co R ci (8) T fo ( z ) T ci ( z ) = q ( z ) ( R ci + R fo ) htc g ( z ) (9) ffT max ( z ) T fo ( z ) = q ( z ) 4 k f ( z ) (10) Axial Dependence (2) Typically only T m ( L / 2) & P ( L / 2) coolant bulk temperature, pressure at inlet are known. T m ( z ) must be determined from an energy balance. Neglecting boiling for the moment: q ( z ) dz = c p ( z ) mdT m (11) dT m dz = q ( z ) c p ( z ) m (12) T m ( z ) = T m , in + Z z L / 2 q ( z ) c p ( z ) m dz (13) Axial Dependence (3)...
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 Fall '11
 Schubring

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