Boiling_Handout_1_SOLUTIONS

Boiling_Handout_1_SOLUTIONS - Boiling Hand-out 1 SOLUTIONS...

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Boiling Hand-out 1 SOLUTIONS– D. Schubring 1 Consider the following boiling water reactor case: Pitch = 16 mm (1) D rod = 12 . 5 mm (2) T sat = 250 C (3) T wall = 257 C (4) x e = x = 0 . 15 (5) G = 1800 kg m - 2 s - 1 (6) 1. Compute the pitch-to-diameter ratio, the ratio between equivalent round tube Nu and that in the rod bundle, and the hydraulic diameter of a sub-channel. Assume an infinite rod array and use Equation 10-101b to compute ψ . P D = Pitch D rod (7) P D = 16 12 . 5 (8) P D = 1 . 28 (9) ψ = 1 . 826 P D - 1 . 043 (10) ψ = 1 . 826 × 1 . 28 - 1 . 043 (11) ψ = 1 . 294 (12) D h = 4 A Per w (13) D h = 4 ( Pitch 2 - π 4 D 2 rod ) πD rod (14) D h = 4 ( 16 2 - π 4 12 . 5 2 ) π 12 . 5 (15) D h = 13 . 59 mm = 0 . 01359 m (16) 2. Compute q 00 using the simple Thom correlation, further assuming that q 00 increases by the same factor ( ψ ) as does a heat transfer coefficient. q
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This note was uploaded on 10/22/2011 for the course ENU 4134 taught by Professor Schubring during the Fall '11 term at University of Florida.

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Boiling_Handout_1_SOLUTIONS - Boiling Hand-out 1 SOLUTIONS...

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