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Boiling_Handout_2_SOLUTIONS

# Boiling_Handout_2_SOLUTIONS - Boiling Hand-out 2 D...

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Boiling Hand-out 2 – D. Schubring 1 Review Example 12-3 and the closely related Problem 12-5 (and extension to critical channel power) that was solved in class. Repeat these computations ( i.e. , apply the Biasi, Bowring, and CISE-4 correlations to a system with a D of 15 mm, G of 1500 kg m - 2 s - 1 , and a L of 4 m. Solutions Biasi Correlation At the mass flux given, both parts of the correlation must be checked. Using 12-71a first: q 00 Biasi,A = 2 . 764 × 10 7 (100 D ) - n G - 1 6 h 1 . 468 FG - 1 6 - x i (1) p bar = 68 . 9 (2) n = 0 . 4 (3) F = 0 . 7249 + 0 . 099 p bar exp ( - 0 . 032 p bar ) (4) F = 0 . 7249 + 0 . 099 × 68 . 9 exp ( - 0 . 032 × 68 . 9) (5) F = 1 . 477 (6) q 00 Biasi,A = 2 . 764 × 10 7 (100 × 0 . 015) - 0 . 4 1500 - 1 6 h 1 . 468 × 1 . 477 × 1500 - 1 6 - x i (7) q 00 Biasi,A = 6 . 946 × 10 6 [0 . 6409 - x ] (8) A second equation between q 00 and x is from an energy balance, as in Example 12-3: x = 4 q 00 Biasi,A L GDh fg - Δ h sub h fg (9) x = 4 q 00 Biasi,A 4 1500 × 0 . 015 × 1 . 51 × 10 6 - 0 . 389 × 10 6 1 . 51 × 10 6 (10) x = 4 . 709 × 10 - 7 q 00 - 0 . 2576 (11) This is now a 2-by-2 system whose solution is: q 00 Biasi,A = 1 . 46 MW m - 2 (12) x = 0 . 431 (13) Now employing 12-71b; the equation from the energy will not change.

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