EML4550HW9ans

EML4550HW9ans - Givens: Angle of attack (): Wind Velocity...

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Givens: Wind Velocity (u): Angle of attack ( α): u5 m s 5.05 m s , 10 m s .. := α 4deg := Rotor Diameter (D): Area of Rotar (A) D5 0 m := R D 2 := R2 5 m = A π R 2 := Angular Velocity ( Ω ): Number of Rotors (n): Ω 25rpm := n 3 := ω T Ω := ω T 2.618 rad s = c p_max .5926 := The density of air at se level and 25C: ρ 1.184 kg m 3 := From Lecture 21 slide 13 chart for drag coefficient for this airfoil: c d .01 := Coefficient of lift (c.1): c 1 2 πα := c 1 0.439 = Blade tip speed ( λ ): λ u () ω T R u := Set tip speed range to determine maximum power coefficient: λ max 0 .02 , 16 .. := Coefficient of performance as a function of tip speed ration (c.p): c p λ max 16 27 λ max ⋅λ max 1.32 λ max 8 20 2 + n 2 3 + 1 .57 λ max 2 c 1 c d λ max 1 2n + :=
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EML4550HW9ans - Givens: Angle of attack (): Wind Velocity...

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