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**Unformatted text preview: **. 6 e-k 1 . Now solve for k : 57 . 2 = 10 + 51 . 6 e-k 47 . 2 / 51 . 6 = e-k ln(47 . 2 / 51 . 6) =-k k = . 0891 . Now solve T ( t ) = 98 . 6, that is 98 . 6 = 10 + 51 . 6 e-. 0891 t . We get t =-6 . 07, following the same arithmetic steps displayed above. This means that the murder was committed 6.07 hours before 2 A.M. , namely, about 7:56 P.M. of the previous day. Solution 2 : Assume that time t = 0 corresponds to the time of death, so T (0) = 98 . 6. Now proceed exactly as in Example 5, p. 319....

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