sandler_sm_06_07

sandler_sm_06_07 - 6 6.7 (a) Ideal gas PV = NRT N= c (50...

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6.7 (a) Ideal gas PV NRT N = = () + ×× = 50 bar 100 m 27315 150 8314 10 1421 2 3 3 K bar m kmol K kmol ch .. . Energy balance, closed nonflow system UQ P d VQW =− =+ z . However, for ideal gas U = 0 since T is constant (isothermal). Thus WQ P d V NRT V dV NRT V V NRT P P Q × × + × F H I K =× = z z ln ln . 2 1 1 2 3 1421 27315 150 50 300 8959 10 8959 8959 kmol 8.314 J mol K kJ MJ MJ l n Also, by Ideal Gas Law at fixed T and N PV V V P P 11 2 2 2 1 1 2 100 m 50 300 1667 =⇒ = = ×= 33 m . (b) Corresponding states TP Z HH T SS rr C IG IG initial state final state 1.391 300 73.76 cal mol K cal mol K + == = 150 27315 304 2 1391 50 7376 0679 094 07 04 4 067 0765 45 2 4 . . . . . . . . Number of moles of gas = = N PV ZRT 1512 . . . kmol ( 1421 . = PV RT from above) Final volume V ZNRT P f f = ×××× + 1512 10 27315 150 300 2 . . = 1356 m . 3
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Energy balance on gas: UQW = + Entropy balance on gas processes in gas are reversible: S Q T SS =+ = gen gen 0 . Therefore S Q T = or QTS =∆ S S S N S SN S S N P P NN WU QN UUQN HHN P VP V fi f f f i ii f i f f i i =−= −= − + − −− =−× −× () R S T U V W =− − R S T U V W =− == + ×× = −− =
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This note was uploaded on 10/22/2011 for the course ENG 101 taught by Professor Yukov during the Spring '11 term at UCLA.

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sandler_sm_06_07 - 6 6.7 (a) Ideal gas PV = NRT N= c (50...

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