resolutionEGsshorter

resolutionEGsshorter - = Resolution Example 1: All hounds...

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====================== Resolution Example 1: All hounds howl at night. all X (hound(X) -> howl(X)). Anyone who has any cats will not have any mice. (not(exists Z Light sleepers do not have anything which howls at night. all X (ls(X) -> (not(exists Y John has either a cat or a hound. (cat(X) or hound(X))). Conclusion: if John is a light sleeper, then John does not have any mice. Negation of the goal: Clausal form: 1. not hound(X) or howl(X). 2. not have(X2,Y2) or not cat(Y2) or not have(X2,Z2) or not mouse(Z2). 3. not ls(X3) or not have(X3,Y3) or not howl(Y3). 4.a have(john,c1). 4.b cat(c1) or hound(c1). 5.a ls(john). 5.b have(john,c2). 5.c mouse(c2). Resolution proof: [1,4.b:] 6 cat(c1) or howl(c1) [2,5.c:] 7 not have(X2,Y2) or not cat(Y2) or not have(X2,b) [7,5.b:] 8 not have(john,Y2) or not cat(Y2) [6,8:] 9 not have(john,c1) or howl(c1)
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This note was uploaded on 10/22/2011 for the course CS CS 2710 taught by Professor Wiebe during the Fall '11 term at Pittsburgh.

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resolutionEGsshorter - = Resolution Example 1: All hounds...

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