EE201 Exam1 Sp2010 Solutions-CA

EE201 Exam1 Sp2010 Solutions-CA - CalPoly Electrical...

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Unformatted text preview: CalPoly Electrical Engineering Department EE 201: Electric Circuit Theory Exam 1 Note: 0 Closed Book and Closed Notes. 0 Reference attached 0 Units shown are in Ohms, Amps, Volts, and Degrees. 0 Use the backsides of the exam pages, for more paper. 0 Pick the best answer. 0 Answer all questions! 0 All problems are weighted equally 0 u = ‘micro’, n = ‘nano’, m = ‘milli’ Name: S<jlsb4“h0“15 WRITE NAME ON SCANTRON Exam Code: E§§IFORNIA 2 WRITE EXAM CODE ON SCANTRON under ‘Test’ Turn in both exam and scantron 1) Given the following Thevenin model, select the equivalent Norton model. IN is given in Amps, RN in Ohms. QO’A- a 2) Find RN for a Norton model of the following circuit. Answer in Ohms. C) 15.0 D) 60.0 2A) 7.5 3) Select a circuit that could be described with a Thevenin model having parameters: Vth = 5V and Rth = 10 Ohms. ,gdfii \/%’E& I , a " 3 ha ha. 5“ ffi-a 10V 10)] “N b b . ~ 5 4) Given the following circuit, find 12. Answer in mA. '9’? Jr, IT 7‘ Bi”. : film} (W e qo‘HlJL (La 1 ': ‘ 7v” 1‘- 5" -» . to 30 4A) 77 B) 100 C) 11 D) 149 V Source A Absorbing_ B Absorbing_ C Delivering Delivering to 'i‘ F .——-— 9‘0V V “30 ’30 , 9 V2 2’ 6A) 1 6B) 15 6C) 20 6D) 60 7) Find R1 such that the current downward through the display is 0.1 mA, when 12 = 100 mA. Select the closest answer in Ohms. I 0.1 = (00‘ R, R\ K. to «‘L‘fi' "‘ *4“. —> EL 1000 )+ £1 ‘0 )0 7A) 10‘4 B) 10'2 c) 102 D) 10“ 8) What is Il? Let Is = 2A. Answer in Amps. 1.4, e N079 Vs‘ ‘0 '3 J“: :0 8A) —2 c) 2 D) 10 9) Are the sources Va, Vb delivering or absorbing power? Let Va = 10V and Vb = 20V. 71‘ J! G JIM Va . v 9 9 2322:5139— \° . . Delivering Delivering 10) What value of Rm” would receive maximum power? Hint: make a Thevenin equivalent to the left of the a—b terminals. Let Rq=5 Ohms and RQ=10 Ohms. Answer in Ohms. Rea 7' [0.1L 20 D) 35 11) If the resistance of the 100 Ohm load decreased by a factor of 2, how would the power EJto the load change? 2. 1 'z c“ v _ 1L '0 10,- PL ’0 Pk "‘ a a mo a 5-0 " PL. a. Increase 2X umJL Decrease 2X 6, : P : Q..P C Increase 4x L L D Decrease 4X 12) Which equations might be associated with the following circuit? \0(Iz~31;) + (or; + 10 (gr-3:3) =0 ‘0 (£3’1‘> 4" ~Iz) .{o :0 IOJL v/ ng A: —10 I1 + 30 I2 — 10 I3 0 E —10 Il + 10 12 + 20 I3 12 B) B only C) Both D) Neither H H O BB 201 — Reference Guide — Exam 1 DePiero - Ohm’s Law 0 V = IR 0 Power and Passive Sign Convention 0 P=Vl> 0 for power absorbed o P=VI=IZR=V2/R o Combining resistors in series RT 2 R1 + R2 + L + RN 1 1 1 1 e~+—~+L +x R1 R2 RN 0 Combining resistors in parallel RT = o Kirchoff’s Voltage Law _ O o "The sumofthe voltages around any loop is zero" 1‘ _ - Kirchoff’s Current Law 0 “The sum ofthe currents into a node is zero” 211, : O 0 Voltage Divider Ra Va : VTOTAL R R a + b 0 Current Divider I I l/Ra a : TOTAL l/Ra +1/Rb o Thevenin and Norton Equivalents O VTH = Voc o IN = lsc O RTH = RN 0 VTH = IN RN ...
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This note was uploaded on 10/24/2011 for the course EE 251 taught by Professor Arakaki during the Spring '08 term at Cal Poly.

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EE201 Exam1 Sp2010 Solutions-CA - CalPoly Electrical...

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