This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: at 432nm, and 408nm (blue and violet). E = N a hc / E = (6.022x10 23 )(6.626x10-34 )(3.00x10 8 ) / For a = 656nm E 2 = 182.5 kJ/mol b = 485.2nm E 3 = 246.7 kJ/mol c = 432 nm E 4 = 277.1 kJ/mol d = 408 nm E 5 = 293.4 kJ/mol Conclusion : Our unknown was determined to contain Potassium, Calcium, and Chlorine because each of the wavelengths observed corresponded with one of these elements. The partial energy diagram was constructed for Hydrogen: E 5 d E 4 c E 3 b E 2 a 2...
View Full Document
This lab report was uploaded on 02/04/2008 for the course CHEM 2070 taught by Professor Chirik,p during the Fall '05 term at Cornell University (Engineering School).
- Fall '05