Optical Spectroscopy - at 432nm and 408nm(blue and violet...

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Optical Spectroscopy October 22, 2007 1
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Results and Discussion: Observing the emission spectrum of certain elements enabled us to understand the composition of mixtures containing those elements. Using what we observed in each individual elements, we were able to understand what was in out unknown mixture. We observed wavelengths of 766nm, 622nm, and 588nm in our unknown mixture 4. The second objective of our lab was to construct a partial energy level diagram for Hydrogen. The emission spectrum of Hydrogen was recorded as follows: The wavelengths recorded from the spectrum were 656nm, 485.2nm, and barely noticeable ones
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Unformatted text preview: at 432nm, and 408nm (blue and violet). ∆E = N a hc / λ ∆E = (6.022x10 23 )(6.626x10-34 )(3.00x10 8 ) / λ For λ a = 656nm ∆E 2 = 182.5 kJ/mol λ b = 485.2nm ∆E 3 = 246.7 kJ/mol λ c = 432 nm ∆E 4 = 277.1 kJ/mol λ d = 408 nm ∆E 5 = 293.4 kJ/mol Conclusion : Our unknown was determined to contain Potassium, Calcium, and Chlorine because each of the wavelengths observed corresponded with one of these elements. The partial energy diagram was constructed for Hydrogen: E 5 λ d E 4 λ c E 3 λ b E 2 λ a 2...
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