03ECE108HWresistiveloadMOSInverter

03ECE108HWresistiveloadMOSInverter - ECE108 ESENER 3.1...

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ECE108 ESENER 3.1 RESISTIVE LOAD MOS INVERTER EXERCISE ___________________________________________________________________________ Assume: V DD = 25V R D = 5K V T = 3V k = 2mA/V 2 Find output voltage for V in = 2V, 4V, 6V a. V in = 2V V GS = V in = 2V < V T DRIVER OFF I D = 0, V DS = V DD - R D I D = V DD = 25V b. V in = 4V GS V = in V = 4 T V DRIVER ON SAT? LINEAR? S V DD R (LOAD) D V G + V in = V GS DRIVER V 0 = V DS +
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Esener ECE 108 3. 2 Assume SAT D I = k 2 4 - 3 ( 29 2 = 1 mA V DS = V DD - I D R D = 25 - 1mA 5K = 20V Check V DS > V GS - V T 20V > 4-3 Yes SATURATED V in = 4V => V O = 20V c. V in = 6V V GS = V = 6 > V T DRIVER ON SAT? LINEAR? Assume SAT I D = 1 6 - 3 ( 2 = 9 mA V DS = 25 - 9(5) =- 20 V NOT POSSIBLE S V DD R (LOAD) D V G + V in = V GS DRIVER V 0 = V DS +
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Esener ECE 108 3. 3 Assume Linear Pull down current I D = k V GS - V T ( 29 V DS - V DS 2 2 = 23 V DS - 1 2 V DS 2 [ ] Pull Up Current 25 () 5 DS D L D D DS V I K VV - = -= LOAD CURRENT = DRIVER CURRENT Which leads to a second order equation with two possible solutions V DS 2 - 6.2 V DS + 5 = 0 V DS = 6.2 ± 38.44 - 20 2 = 0.95 V or 5.25 V V DS = 5.25 V GS - V T = 3 V V DS V GS - V T SAT (Disagreement with assumption!)
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This note was uploaded on 10/24/2011 for the course ECE 108 taught by Professor Kennethy.yun during the Spring '08 term at UCSD.

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03ECE108HWresistiveloadMOSInverter - ECE108 ESENER 3.1...

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