TV_EOQ_Problems - IE 251 Production and Inventory Control...

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Unformatted text preview: IE 251 Production and Inventory Control Exam #1 Fall 2010 4...(35 pts) Consider the following Wagner-Whitin table: A s 250 h s 1.00 a) After considering the coefficient of variation of the demand pattern, is there justification for simply using the Fixed EOQ coverage policy? b) Fill in the appropriate values for cells with question marks. c) Cross out cells that would not have needed to be filled in because they will never provide the answer for an optimal policy. d) Identify the o timal coverage policy from the table. 2— 'L n . 95 S bL'H lMimi-Hm +2002} {an} _ )3. fl! = ( DO .’ I n 7. 7‘ CZ yd (20+ muse flan—#2007 J = l ‘1; "ijf'fwl-x\ = (M3214 3/375? >.a 5‘q140a \_\1:.M . . .1 (5.) A: .250 + (uan = 35° (CB 01W MAW‘ g: 450 + (3063(3) =1$50 AW (wt 93 2501-350 =é00 >A‘25° 9" 95" +3°°m :4” (CH Q4: 6'00 (Tumlw> g: 490t200(2\:’3‘9° 625:15‘0 (menu) F: 250 r 200m =Iofi'0 @5140 (WWW IE 251 Production and Inventory Control Exam #1 Fall, 2009 4...(27 pts) Assuming setup cost is $220 and inventory holding cost per unit per week is $.50, consider the following Wagner-Whitin table: Demand 120 55 124 210 70 300 135 90 124 260 Week 1 2 3 4 5 1 220.00 247.50 371.50 65060 32/560 2 440.00 502.00 712.00 817.00 3 467.50 572.50 642.50 591.5 4 A 626.50 '—-—-—_" H 5 3'“ S-rlzoj 792.50 6 ,_ 846.50 914.00 1,004.00 1,190.00 1,7 .00 79.1.3 +(.$)(3ab\f1:—7‘% X 7 » 1,066.50 1,111.50 1,235.50 1,63%0 (l . .5 + 2 .5 13 1134 8 C ( 5) I D 1,196.00 1,4 .00 9 Cith +294: 1,224.00 1,354.00 10 1,410.00 a) Fill in missing cells A, B, C, and D b) Place “X” in each cell that would have been unnecessary to fill in to get to a solution. c) Determine the optimal ordering policy from the table. d) Determine the Silver-Meal ordering policy for this problem. Let) L WHATS T T, mm.) /1, I an 0 T .2 J o .9. .220 1- $51.3: I 7- 3%;” 4 «Haggai 5 9115+ 12+m Mama : HS. 3 M FT’V‘W "_ .. -- T,=1 $62,217; T2 0"“ (T73 /TL T 1; o 3331:4041. TL mum/T, 1 [220+ am 0511/: = 142.5 ‘5 1 .220 ,N, 3 [3:15 + 70ml“ : £347? a 2.20 21361.53 2mm, 53:3 _ \: 4 [Sh/14°" (“Sn/‘1- :lims 3 £737.3’rr‘loufl/5wai3 Qyflv 4 [377.5'1— 13+ (1333/4 : 140.2% IE 251 Production and Inventory Control Exam #1 Fall 2008 2...(30 pts) “nun- Let A = $200 , h = $4/unit/period , and assume initial inventory = 0 a) determine a Part Period Balancing coverage of the 6 periods of demand b) determine the best coverage of the first 3 periods using the Wagner- Whitin algorithm 3 4 5— Q ((1') t l .2 — “ " 0 35m mmmwma Ag Kw} é’/— . -‘ E} (15mm) 2600 0' (saw ‘ " ‘ 572.70 MOM :. (new: afraid I M Wt [83‘ mdu: Lu. [ma 3 4M “Waco IE 251 Production and Inventory Control Exam #1 Fall 2008 2...(3o pts) nun- Let A = $200 , h = $4/unit/period , and assume initial inventory = 0 a) determine a Part Period Balancing coverage of the 6 periods of demand b) determine the best coverage of the first 3 periods using the Wagner- Whitin algorithm ' 1c F‘(K) 2W (t-nru-Dt—l— F('3..Q73 =5 “35K PU) ra’loo +0 '2 6200 . 3=l : 300 + (Lucas) 4- o 2 340 : 3+0 Fm) : h ‘ ‘ E 3“— a) A J=9~= 400 + goo :: 400 (g - . 374 ’- Aoo + 4m» 1- mm) 200 + o : H33 :WM < < ) [4+0 A 3:; 1 260 + 4(2003—1—290 2 [goo : 5+0 3*:5 IE 251 Production and Inventory Control Exam 1 Fall 2006 3...(26 pts) ‘ Time-varying demand. A=$120 , v=$4 , rp=$.5/$/period n “m a) Determine a part period balancing coverage. b) Fill in the missing cost elements in the following Wagner—Whitin table and determine the corresponding optimal coverage. Demand 50 45 Month 1 2 3 4 5 6 120.00 160.00 640.00 1,000.00 1,550.00 240.00 14.0 560.00 830.00 1,270.00 .220 440.00 620.00 950.00 280.00 540 01cm 7o.£.~.pm'od_ y (b0 400.00 mm (‘2 5““ iammL 5‘ ‘o’ide 55-30. laminate (a.\ We“ W¢W£MjnAmAW%T ZA=120 : W hgkhfznidl z o l 10(2):!40 3 $4511) “to 1+ ’fOt-Yoflk'qz'fillo] "1'43 ) Q\:7o mathpmqt l o 9. 45(2\=Q© 3 q°+5§(1\(27=3w] T=9~ , 34:125‘ IE/MSE 425 Resource Allocation and Production Planning Exam 1 Fall 2004 3... EOQ with Time-varying Demand Utilizing the following data: Determine the percentage error as measured by the TRC value if Period Part Balancing is used instead of the Wagner-Whitin Method to determine a lot sizing policy for the 5 period horizon given above. i Z ‘5 Li ‘5 /.20 1.70.9 1.20.“! [17.20.114.210: 3+0 14-0 344.2 £55.? a I 240.? .245 .7503 240.4 244.8 V|~FWN‘ A=€25° f I .1 3 4- F d, 7 8’ 7 la n :2_ Ho 90 (.25 4o loo Roe I50 56 60 fa 70 7o .. war-w a (A) Allow—711ml 1091143;ij (5.) WWW/KMAIMW Mat 11‘pr em JwaaaLA. '5’ (a) 4554 770M amu- 1% zoom HMMLL. (A) €m$§ 70W ’6 id“ £0=J¢a~uoius t, _ __ T |_ i. i :L. 12,. 1 350 350+ 7° _ 33mm 7 a 4M 794:1“ -— a 5 950 45M” : 310+(2mn I 5 2 -— ,1 1' 3 1'63 9. s 350 25°”‘m ._ 450+Rafl) ‘225' ._._—— = -— .1 3 .252: :L 7 450 450+?!“ :140 290+ 2am _ 4m+ 3m) _ .1 3 435.3 T min: 3: [0 J50 i 35D :90 2nd 34-01-205) :léo -___ M3 ; .‘. Q A, G} = 250 ._., to 1 Q5 3:30 62,, = .750 Q3: (50 Q1:;.z¢o l F.1ng Eda (wag; '. - to T '1 J— 3: 3:. Ti“ T 17° _ 250* g 3 :20 no 240* 3 ¢ 300* 850 l 7 (So 190 Ho * 3 ’9 ‘10 {so 250 * '5 M'M EOCQ 24,536 w‘md 73¢ (3355,43 = .240 + 450 = 740 5%“ Ema mqifiaej = 4‘10 +250 = 7‘fo ma” “figs—fl ted defiané pattezn f0- :55 LELt ? tzmlnr of ordar quantities iafiacmfiég = Gréer quaLtity aha Sil?er—Mwa1 ceatage cost penalty i3?ulvea &“ = thls application flantn £3 5 5 7 50 'II'OG 293 106} I 75": Q5”) 5cm -.T_ l.‘ ’39 I ‘ {go Ham“) 2 ’M? = 120 Z "‘“T {32/1 7mm ' ={2g 3 m wavy-are) we 3 240 + (SaxJYz'J ._._ go 3 - '3 4 0770 {- (WEN-9(3) _______________.=:225' zil- G’z? 1m a.= 5’50 ' ' I #570 TRCLPM‘ = Baffin-i- (zap-Ha» +xm)(.5) = 2%? PCP: “a 70 TRqsfl‘: 27o+3w=570 ' . . . IE 251 Production and Inventory Control Exam 2 Fall 2005 1... Time—varying Demand Lot Sizing Assume inventory carrying cost is $2 per unit per period and 4 periods of demand are as given in the following table: t 1 2 3 4 D(t) 7o 20 100 50 (a) (12 pts) With A = $35, provide a lot size coverage of the 4 periods using the Silver-Meal heuristic. (b) (13 pts) Determine the range of values for A that would lead to an order arriving in period 1 covering the first 3 periods, using the Part Period Balancing heuristic. (m ' (wt A41:— #1 T = T! (CL) . Am“ I 9. ___.g_ aw. .. J. = 1 352+ 35+(:7(2o\ :57; I .3. = 2 3g* 35+:zzaon : a“. 1 '1 = 3 35* 3,—w—S* “"3 =41? l 2 .3. = 4 7w“ v I Lot-5n ~14 .cowz : a; =1;l “all; J/ (b) I (T\ = M4906 z‘(az gamma; .3 T_fw¢'¢,i& I (z) = mm =40 1(33 = 40 + a (21mm = 440 1(4) = 4-40 + 3(2)(5‘o\ = 740 Ian-1(1) :Jowudrmuim A= z 0-K A : I(53+I(4\ Z. 7- 14o = 540 / \ IE 251 Production and Inventory Control Exam 2 Fall 2005 2... Wagner-Whitin Algorithm Given a setup cost of $130 and an inventory holding cost of $0.60 I unit / month, the following Wagner-Whitin table may be constructed: Demand 10 62 12 130 154 129 88 52 Month 1 2 3 4 5 6 7 8 1 $130.00$167.20$181.60$415.6$1,172.20$1,489.00$1,707.40 $260.00 $267.20 $423.20$7oo.4o $1 ,010.00$1,274.00$1,461.20 $375.20$560.00 $792.2051,003.40$1 159.40 $311.60$404.00 $558.80 $717.2 $534.00 $586.8 $649.0 Cowman.an (a) (13 pts) Fill in the 10 missing entries. (b) (12 pts) Determine the optimal lot-ordering plan from the table and the cost of that plan. (b3 W magi): C 3 6 447.2 5 4 40+ I§~_\- l l8l.éo ,/’ 4 A v 7* ww“~\ ...
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