EE2005-Tutorial02-Solution - NATIONAL UNIVERSITY of...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
NATIONAL UNIVERSITY of SINGAPORE Department of Electrical and Computer Engineering EE2005 – Electronics Tutorial 2 Solution Q1. ] 025 . 0 737 . 1 /[ 8 ) /( ) 10 937 . 7 ( × × = D T D V nV V S D e mA e I I (a) Using the constant-voltage-drop model, V R = (5 – 1 – 0.7) V = 3.3 V Ω = k V I R D 2 = 1.65 mA (b) By iteration, If I D = 1.65 mA, the exponential diode equation evaluates V D to be ) ln( S D T D I I nV V = ) 10 937 . 7 65 . 1 ln( ) 025 . 0 )( 737 . 1 ( 8 mA mA × = = 0.73171 V If V D = 0.73171 V, V R = (5 – 1 – 0.73171) V = 3.26829 V Ω = k V I R D 2 = 1.63415 mA If I D = 1.63415 mA, the exponential diode equation evaluates V D to be ) ln( S D T D I I nV V = ) 10 937 . 7 63415 . 1 ln( ) 025 . 0 )( 737 . 1 ( 8 mA mA × = = 0.73129 V If V D = 0.73129 V, V R = (5 – 1 – 0.73129) V = 3.26871 V Ω = k V I R D 2 = 1.63436 mA If I D = 1.63436 mA, the exponential diode equation evaluates V D to be ) ln( S D T D I I nV V = ) 10 937 . 7 63436 . 1 ln( ) 025 . 0 )( 737 . 1 ( 8 mA mA × = = 0.73129 V
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
The converged I D and V D are 1.6344 mA and 0.7313 V, respectively. (c) V R = (5.1 – 1 – 0.7) V = 3.4 V Ω = k V I R D 2 = 1.7 mA By iteration, If I D = 1.7 mA, the exponential diode equation evaluates V D to be ) ln( S D T D I I nV V = ) 10 937 . 7 70 . 1 ln( ) 025 . 0 )( 737 . 1 ( 8 mA mA × = = 0.73300 V If V D = 0.73300 V, V R = (5.1 – 1 – 0.73300) V = 3.367 V Ω = k V I R D 2 = 1.68350 mA If I D = 1.68350 mA, the exponential diode equation evaluates V D to be ) ln( S D
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 8

EE2005-Tutorial02-Solution - NATIONAL UNIVERSITY of...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online