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Unformatted text preview: thickness of 0.5 μ m = 0.5 2 /0.53 + 0.5/2.9 - 0.144 = 0.50 hrs. In the unoxidized region, 0.5 hours oxidation yields This result can also be obtained using Fig. 3.6 in a manner similar to the solution of Problem 3.13. Note that this result is almost independent of the temperature chosen. The growth in the unoxidized area ranges from 41 nm at 1000 o C to 44 nm at 1200 o C....
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This note was uploaded on 10/24/2011 for the course EEE 5322 taught by Professor W.r.eisenstadt during the Fall '10 term at University of Florida.
- Fall '10