AOE3104.Homework1.Solutions

# AOE3104.Homework1.Solutions - Homework#1 Solution 1 One...

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Homework #1 Solution 1. One side of the manometer is attached to the test item while the other is vented to the atmosphere. The pressure difference, the test value of gauge pressure, is manifested in the height differential in the water manometer. h s m m Kg h g P P o a m Δ = Δ = 2 3 / 807 . 9 / 1000 ρ where is the absolute measured pressure and is the atmospheric pressure. m P a P The results are: cm h 0 . 4 = Δ Pa s m m Kg P P a m 100933 04 . 0 / 807 . 9 / 1000 2 3 = = cm h 5 . 1 = Δ Pa s m m Kg P P a m 101472 015 . 0 / 807 . 9 / 1000 2 3 = + = cm h 5 . 10 = Δ Pa s m m Kg P P a m 102355 105 . 0 / 807 . 9 / 1000 2 3 = + = 2. Standard sea-level values: Additional data for the ISA standard atmosphere is given in the following: The mathematical models for atmospheric properties in the troposphere (0-11 km) and the lower part of the stratosphere (11-20 km) were described in class and in various notes. A MATLAB routine to implement these is available here. Note that this routine is written to correctly handle vector input, that is, the altitude

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AOE3104.Homework1.Solutions - Homework#1 Solution 1 One...

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