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Homework #1 Solution
1.
One side of the manometer is attached to the test item while the other is vented to
the atmosphere. The pressure difference, the test value of gauge pressure, is
manifested in the height differential in the water manometer.
h
s
m
m
Kg
h
g
P
P
o
a
m
Δ
−
=
Δ
−
=
−
2
3
/
807
.
9
/
1000
ρ
where
is the absolute measured pressure and
is the atmospheric pressure.
m
P
a
P
The results are:
cm
h
0
.
4
=
Δ
Pa
s
m
m
Kg
P
P
a
m
100933
04
.
0
/
807
.
9
/
1000
2
3
=
−
=
cm
h
5
.
1
−
=
Δ
Pa
s
m
m
Kg
P
P
a
m
101472
015
.
0
/
807
.
9
/
1000
2
3
=
+
=
cm
h
5
.
10
−
=
Δ
Pa
s
m
m
Kg
P
P
a
m
102355
105
.
0
/
807
.
9
/
1000
2
3
=
+
=
2.
Standard sealevel values:
Additional data for the ISA standard atmosphere is given in the following:
The mathematical models for atmospheric properties in the troposphere (011 km)
and the lower part of the stratosphere (1120 km) were described in class and in
various notes. A MATLAB routine to implement these is available here. Note that
this routine is written to correctly handle vector input, that is, the altitude
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 Spring '08
 DR.CRAIGWOOLSEY

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