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Unformatted text preview: Nguyen, Thanh Homework 11 Due: Feb 29 2008, 7:00 pm Inst: Weathers 1 This printout should have 12 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points A positively charged particle moving paral lel to the yaxis enters a magnetic field (point ing toward the top of the page), as shown in the figure below. y z v x ~ B ~ B + q Figure: is in the xdirection, is in the ydirection, and k is in the zdirection. What is the initial direction of deflection? 1. b F = k 2. b F = 3. b F = + 4. b F = + 5. b F = correct 6. b F = + k 7. ~ F = 0 ; no deflection Explanation: Basic Concepts: Magnetic Force on a Charged Particle: ~ F = q~v ~ B Righthand rule for crossproducts. b F ~ F k ~ F k ; i.e. , a unit vector in the F direc tion. Solution: The force is ~ F = q~v ~ B . ~ B = B + k , ~v = v ( ) , and q > , therefore , ~ F = +  q  ~v ~ B = +  q  v B h ( ) + k i = +  q  v B ( ) b F = . This is the sixth of eight versions of the problem. keywords: 002 (part 1 of 1) 10 points A proton moving at 1 . 1 10 6 m / s through a magnetic field of 7 . 4 T experiences a magnetic force of magnitude 5 . 7 10 13 N. The charge of proton is 1 . 60218 10 19 C and the mass of proton is 1 . 67262 10 27 kg. What is the angle between the protons velocity and the field? Correct answer: 25 . 9164 . Explanation: Let : E = 5 . 7 10 13 N , B = 7 . 4 T , v = 1 . 1 10 6 m / s , q p = 1 . 60218 10 19 C , and m p = 1 . 67262 10 27 kg . The Lorentz force acting on a moving charged particle in a magnetic field is F = q v B sin , where q is the charge, v is the speed, B is the magnetic field. So thus the angle between the velocity and the field is = arcsin F q v B = arcsin (5 . 7 10 13 N) (1 . 60218 10 19 C) 1 (1 . 1 10 6 m / s) (7 . 4 T) = 25 . 9164 . Nguyen, Thanh Homework 11 Due: Feb 29 2008, 7:00 pm Inst: Weathers 2 keywords: 003 (part 1 of 3) 10 points The magnetic field over a certain range is given by...
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