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Unformatted text preview: Nguyen, Thanh Homework 21 Due: Apr 22 2008, 7:00 pm Inst: Weathers 1 This printout should have 14 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 2) 10 points An object is p = 44 . 6 cm in front of a concave mirror. Its real image height is 7 times larger than the object height. p h What is the location of the image? Correct answer: 312 . 2 cm. Explanation: 1 p + 1 q = 1 f = 2 R m = h h = q p Concave Mirror f > > p > f f < q < > m > f > p > < q < > m > 1 Let : M = 7 and p = 44 . 6 cm . Let the location of the image be denoted as q . q p h h' f R Since the image is 7 times larger than the object, and is a real image, as stated in the problem ( p > 0 and q > 0), the magnification must be negative; i.e. , M = 7. M = h h = q p = 7 , so q = M p = ( 7) (44 . 6 cm) = 312 . 2 cm . 002 (part 2 of 2) 10 points What is the radius of curvature of the mirror? Correct answer: 78 . 05 cm. Explanation: Now that we have q and p , we can find the radius of the curvature via the relationship 1 p + 1 q = 2 R or R = 2 p q p + q = 2 (44 . 6 cm) (312 . 2 cm) 44 . 6 cm + 312 . 2 cm = 78 . 05 cm . keywords: 003 (part 1 of 2) 10 points A concave spherical mirror has a radius of curvature of 34 . 6 cm . The object distance is 9 . 1 cm . h q h p f R Scale: 10 cm = Find the magnitude of the image distance. Correct answer: 19 . 1988 cm. Explanation: 1 p + 1 q = 1 f = 2 R M = h h = q p Concave Mirror f > f > p > < q < > M > 1 Note: The radius of curvature for a concave mirror is positive, R = 34 . 6 cm. Nguyen, Thanh Homework 21 Due: Apr 22 2008, 7:00 pm Inst: Weathers 2 Solution: Substituting these values into the mirror equation q = 1 1 f 1 p = 1 2 R 1 p = 1 2 34 . 6 cm 1 9 . 1 cm = 19 . 1988 cm  q  = 19 . 1988 cm ....
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This note was uploaded on 10/24/2011 for the course PHYS 2220 taught by Professor Littler during the Spring '00 term at North Texas.
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