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Homework_21

# Homework_21 - Nguyen Thanh Homework 21 Due 7:00 pm Inst...

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Nguyen, Thanh – Homework 21 – Due: Apr 22 2008, 7:00 pm – Inst: Weathers 1 This print-out should have 14 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 2) 10 points An object is p = 44 . 6 cm in front of a concave mirror. Its real image height is 7 times larger than the object height. p h What is the location of the image? Correct answer: 312 . 2 cm. Explanation: 1 p + 1 q = 1 f = 2 R m = h 0 h = - q p Concave Mirror f > 0 > p > f f < q < 0 > m > -∞ f > p > 0 -∞ < q < 0 > m > 1 Let : M = - 7 and p = 44 . 6 cm . Let the location of the image be denoted as q . q p h h' f R Since the image is 7 times larger than the object, and is a real image, as stated in the problem ( p > 0 and q > 0), the magnification must be negative; i.e. , M = - 7. M = h 0 h = - q p = - 7 , so q = - M p = - ( - 7) (44 . 6 cm) = 312 . 2 cm . 002 (part 2 of 2) 10 points What is the radius of curvature of the mirror? Correct answer: 78 . 05 cm. Explanation: Now that we have q and p , we can find the radius of the curvature via the relationship 1 p + 1 q = 2 R or R = 2 p q p + q = 2 (44 . 6 cm) (312 . 2 cm) 44 . 6 cm + 312 . 2 cm = 78 . 05 cm . keywords: 003 (part 1 of 2) 10 points A concave spherical mirror has a radius of curvature of 34 . 6 cm . The object distance is 9 . 1 cm . h 0 q h p f R Scale: 10 cm = Find the magnitude of the image distance. Correct answer: 19 . 1988 cm. Explanation: 1 p + 1 q = 1 f = 2 R M = h 0 h = - q p Concave Mirror f > 0 f > p > 0 -∞ < q < 0 > M > 1 Note: The radius of curvature for a concave mirror is positive, R = 34 . 6 cm.

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Nguyen, Thanh – Homework 21 – Due: Apr 22 2008, 7:00 pm – Inst: Weathers 2 Solution: Substituting these values into the mirror equation q = 1 1 f - 1 p = 1 2 R - 1 p = 1 2 34 . 6 cm - 1 9 . 1 cm = - 19 . 1988 cm | q | = 19 . 1988 cm .
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Homework_21 - Nguyen Thanh Homework 21 Due 7:00 pm Inst...

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