Homework_03 - Nguyen, Thanh Homework 3 Due: Sep 11 2007,...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Nguyen, Thanh Homework 3 Due: Sep 11 2007, 7:00 pm Inst: D Weathers 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 2) 10 points Two sides of a triangle are 11 . 2 cm and 20 . 6 cm, with the included angle 118 . a) What is the length of the third side? Correct answer: 27 . 6845 cm. Explanation: Basic Concepts: The Law of Cosines states c 2 = a 2 + b 2- 2 ab cos C The Law of Sines states sin A a = sin C c Solution a c b A C We are looking for the side opposite the given angle so c = p a 2 + b 2- 2 ab cos C 002 (part 2 of 2) 10 points b) What is angle opposite the side 11 . 2 cm? Correct answer: 20 . 9286 . Explanation: sin A a = sin C c A = arcsin a sin C c keywords: 003 (part 1 of 1) 10 points A high fountain of water is located at the center of a circular pool as in the figure. A student walks around the pool and estimates its circumference to be 69 . 4 m. Next, the student stands at the edge of the pool and uses a protractor to gauge the angle of elevation of the top of the fountain to be 64 . 1 . How high is the fountain?...
View Full Document

Page1 / 3

Homework_03 - Nguyen, Thanh Homework 3 Due: Sep 11 2007,...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online