{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Homework_24 - Nguyen Thanh Homework 24 Due Dec 7 2007 7:00...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Nguyen, Thanh – Homework 24 – Due: Dec 7 2007, 7:00 pm – Inst: D Weathers 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points The molar mass of O 2 is 32 g / mol, and the molar mass of He is 4 g / mol. The rms speed of a helium atom at room temperature is 1655 m / s. What is the rms speed of an oxygen (O 2 ) molecule at this temperature? Correct answer: 585 . 131 m / s. Explanation: Let : v He = 1655 m / s , m He = 4 g / mol and m O 2 = 32 g / mol . According to the molecular model of ideal gas, v He = s 3 k B T m He v O 2 = s 3 k B T m O 2 v O 2 v He = r m He m O 2 v O 2 = v He r m He m O 2 = (1655 m / s) s 4 g / mol 32 g / mol = 585 . 131 m / s . keywords: 002 (part 1 of 1) 10 points The universal gas constant is 8 . 31451 J / K · mol. Calculate the change in internal energy of 1 mol of helium gas when its temperature is increased by 6 . 1 K. Correct answer: 76 . 0778 J. Explanation: Given : n = 1 , R = 8 . 31451 J / K · mol and Δ T = 6 . 1 K .
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern