# Quiz5D -   DL section Grade Last 6 digits of...

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Unformatted text preview:   DL section _ Grade: Last 6 digits of student ID ______ 05/04/11 Last name , first name: ________________ ________________ First three letters of your last name ___                   Fexternal  t = Net Impulseexternal =  p=mv            ! "     # \$%   &%"   &%  '(  )* #"   #%* %\$( You know that the net force is zero, which means that F_1 + F_2 + F_3 = 0 You know that the F_3 is vertical and F_1 is horizontal, then F_2.y = - F_3 = - 10 N Because it's a 45 deg triangle then the two short sides have the same length and we can solve for |F_2| = sqrt (10^2 + 10^2) = 14.1 N      %* %\$( You know that the net force is zero, which means that F_1 + F_2 + F_3 = 0 F_1 = - F_2 - F_3 Because you are just focused on the horizontal direction and the angle is 45 degrees then |F_1| = |F_2.y| = = |F_3| = 10 N ! +   )  & *  "#&  \$%& + \$ \$    %  ''*& \$ &  '*  &   !'      ' ,'' -\$   '& *  '* p.in = m v = 6.0 kg 0.5 m/s = 3.0 N s D elta (p) = p.ﬁn - p.in = 2.0 N s p.ﬁn = 3 N s + 2 N s = 5.0 N s p.in object Delta (p) P.ﬁn 3.0 N s 2.0 N s 5.0 N s  . &/0)'   No. The velocity of the object is increasing and that changes its momentum (mass is the same). ...
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