Quiz+1+Section+C+Sol

Quiz+1+Section+C+Sol - D L SE C T I O N 7B.S11 - Quiz 1...

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Unformatted text preview: D L SE C T I O N 7B.S11 - Quiz 1 Last 6 digits of student ID ______ __ Grade: Last name, ______________ 04/06/2011 first name: ______________ First three letters of your last name ___ N o b oo k s o r n o t e s . C a l c u l a t o r s O K . S h o w a l l y o u r w o r k b e l o w . A n s w e r s a l o n e r e c e i v e n o c r e d i t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here is no Kinetic Energy because the water is not moving. There is no Resistance involved in the problem because there is no I (current). There is no pump (your mouth could be thought as a pump, but that's not in the part of the fluid circuit we are analyzing). Delta (p) + Delta (PE)/Vol = 0 where the Delta is referred to the surface of the glass and the top of the straw (just the bottom changes, but that is not in the equation). Because the Delta(h) is the same and they are both open to the atmoshpere then the Delta(p) is the same 2. equal pressure. A% "',0B'$+*3% 202#% 0)% )"*2#@% *)% 0$% +"#% 601(,#% 7#3'-% *$@% "*)% -*+#,% 63'-0$1% 6,'5% 3#6+% +'% ,01"+9% C"#% ,#)0)+*$/ #% 7#+-##$%2'0$+)%-%*$@%.%0)%/0'(/"$!1$12!"9%% % &3% :)% +"#% 2,#))(,#% *+% .( 1,#*+#,% +"*$.% #D(*3% +'.% ',% 3#))% +"*$% +"#% 2,#))(,#% *+% -.% ',% /*$% &'(% $'+% +#33% -0+"% +"#% 104#$% 0$6',5*+0'$;%EF0$+G%+"0$H%*7'(+%+"#%/*)#%-0+"%$'%,#)0)+*$/#%60,)+I9%A$)-#,%-0+"%*%)"',+%)#$ +#$/#%0$/3(@0$1%+"#%#$#,1&% @#$)0+&%)&)+#5)9( % Between A and B, KE goes up (A goes down, v goes up), PE is constant, there is no pump. % % In the case with no resistance is easy to see that the Pressure must go down. % In the %case with resistance the resistance is even "eating" more energy, so pressure is going to be % even less. In the equation both IR and Delta(KE) are taking energy from Delta(P). % 23% J$'-0$1%+"*+% 4.( 5(637(+8#.% 4-( 5(639(+8#.% --( 5(63:(+;% *$@%+"#%,#)0)+*$/#%7#+-##$%A%*$@%K%0)% <(5966(=$(8(>+?( #@A( /*3/(3*+#% .-(5(B.(C(BA%9%( % % Delta(P)_BA = - IR - 1/2 rho Delta(v^2) I = v_B x A_B = v_A x A_A = 0.05 m^3/s Delta(v^2) = 0.25 (m/s)^2 - 0.09 (m/s)^2 = 0.16 (m/s)^2 Delta(P) = - 5 J/m^3 - 80 J/m^3 = - 85 J/m^3 %%%% % %%%%%% %%%%%% % ...
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This note was uploaded on 10/24/2011 for the course PHYSICS 7B taught by Professor Johnconway during the Spring '07 term at UC Davis.

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