Practice Exam 1 - Exam
I
Prac*ce
Ques*ons


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Unformatted text preview: Exam
I
Prac*ce
Ques*ons
 1.

During
a
typical
sexual
life
cycle:

 (a)
haploid
gametes
fuse
in
fer;liza;on
to
form
a
diploid
zygote,
 (b)
diploid
gametes
fuse
in
fer;liza;on
to
form
a
haploid
zygote,

 (c)
meiosis
results
in
the
produc;on
of
diploid
cells,

 (d)
choices
“a”
and
“c”
are
both
correct,
but
choice
“b”
is
not
correct,

 (e)
choices
“b”
and
“c”
are
both
correct,
but
choice
“a”
is
not
correct.

 1.

During
a
typical
sexual
life
cycle:

 (a)
haploid
gametes
fuse
in
fer*liza*on
to
form
a
diploid
zygote,
 (b)
diploid
gametes
fuse
in
fer;liza;on
to
form
a
haploid
zygote,

 (c)
meiosis
results
in
the
produc;on
of
diploid
cells,

 (d)
choices
“a”
and
“c”
are
both
correct,
but
choice
“b”
is
not
correct,

 (e)
choices
“b”
and
“c”
are
both
correct,
but
choice
“a”
is
not
correct.

 2.

In
the
process
of
mitosis,
sister
chroma;ds
become
aCached
to
 kinetochore
microtubules
during:

 (a)
interphase,

 (b)
prophase
,

 (c)
prometaphase,

 (d)
anaphase,

 (e)
telophase.
 2.

In
the
process
of
mitosis,
sister
chroma;ds
become
aCached
to
 kinetochore
microtubules
during:

 (a)
interphase,

 (b)
prophase
,

 (c)
prometaphase,

 (d)
anaphase,

 (e)
telophase.
 3.

Telophase
of
mitosis
is
usually
followed
immediately
by:
 (a)
S
phase,

 (b)
G2
phase,

 (c)
anaphase,

 (d)
metaphase,

 (e)
cytokinesis.
 3.

Telophase
of
mitosis
is
usually
followed
immediately
by:
 (a)
S
phase,

 (b)
G2
phase,

 (c)
anaphase,

 (d)
metaphase,

 (e)
cytokinesis.
 4.

In
the
process
of
meiosis,
pairs
of
homologous
chromosomes
are
 fully
condensed
and
lined
up
on
the
equatorial
plate
at:

 (a)
prophase
I,

 (b)
anaphase
I,

 (c)
anaphase
II,

 (d)
metaphase
I,

 (e)
metaphase
II.
 4.

In
the
process
of
meiosis,
pairs
of
homologous
chromosomes
are
 fully
condensed
and
lined
up
on
the
equatorial
plate
at:

 (a)
prophase
I,

 (b)
anaphase
I,

 (c)
anaphase
II,

 (d)
metaphase
I,

 (e)
metaphase
II.
 5.

During
prophase
I
of
meiosis:
 (a)
chromosomes
replicate,

 (b)
homologous
chromosomes
pair,

 (c)
homologous
chromosomes
are
lined
up
on
the
equatorial
plate
of
 the
cell,

 (d)
homologous
chromosomes
separate,

 (e)
chroma;ds
separate.
 5.

During
prophase
I
of
meiosis:
 (a)
chromosomes
replicate,

 (b)
homologous
chromosomes
pair,

 (c)
homologous
chromosomes
are
lined
up
on
the
equatorial
plate
of
 the
cell,

 (d)
homologous
chromosomes
separate,

 (e)
chroma;ds
separate.
 6.

Given:
In
humans,
being
able
to
roll
your
tongue
(T)
is
dominant
to
 not
being
able
to
roll
your
tongue
(t).

If
a
man
and
woman
who
both
 are
able
to
roll
their
tongues
get
married
and
have
a
child
who
cannot
 roll
his(her)
tongue,
then:

 (a)
both
parents
are
homozygous
recessive,

 (b)
both
parents
are
heterozygous,

 (c)
one
parent
is
heterozygous
and
the
other
homozygous
recessive,

 (d)
either
choice
“b”
or
choice
“c”
could
be
correct,
but
choice
“a”
 cannot
be
correct,

 (e)
any
of
the
choices,
“a”,
“b”,
or
“c”
could
be
correct.
 6.

Given:
In
humans,
being
able
to
roll
your
tongue
(T)
is
dominant
to
 not
being
able
to
roll
your
tongue
(t).

If
a
man
and
woman
who
both
 are
able
to
roll
their
tongues
get
married
and
have
a
child
who
cannot
 roll
his(her)
tongue,
then:

 (a)
both
parents
are
homozygous
recessive,

 (b)
both
parents
are
heterozygous,

 (c)
one
parent
is
heterozygous
and
the
other
homozygous
recessive,

 (d)
either
choice
“b”
or
choice
“c”
could
be
correct,
but
choice
“a”
 cannot
be
correct,

 (e)
any
of
the
choices,
“a”,
“b”,
or
“c”
could
be
correct.
 6.

Given:
In
humans,
being
able
to
roll
your
tongue
(T)
is
dominant
to
 not
being
able
to
roll
your
tongue
(t).

If
a
man
and
woman
who
both
 are
able
to
roll
their
tongues
get
married
and
have
a
child
who
cannot
 roll
his(her)
tongue,
then:

 (a)
both
parents
are
homozygous
recessive,

 (b)
both
parents
are
heterozygous,

 (c)
one
parent
is
heterozygous
and
the
other
homozygous
recessive,

 (d)
either
choice
“b”
or
choice
“c”
could
be
correct,
but
choice
“a”
 cannot
be
correct,

 (e)
any
of
the
choices,
“a”,
“b”,
or
“c”
could
be
correct.
 NOTE:
No;ce
in
answer
“c”
that
one
parent
is
homozygous
recessive.

 This
cross
could
give
you
a
child
who
cannot
roll
his(her)
tongue,
but
if
 that
parent
were
homozygous
recessive,
then
he(she)
would
have
 been
a
non‐tongue
roller,
and
I
said
in
the
“Given”
that
both
parents
 are
able
to
roll
their
tongues.

Be
sure
to
read
the
ques;ons
carefully!
 7.

Given:
In
humans,
having
free
earlobes
is
dominant
to
having
 aCached
earlobes.

A
man
with
free
earlobes
marries
a
woman
with
 free
earlobes
and
they
have
a
child
with
aCached
earlobes.

If
they
 were
to
have
three
more
children,
the
chances
that
the
first
child
will
 have
free
earlobes,
the
second
will
have
aCached
earlobes,
and
the
 third
will
have
free
earlobes
are:
 (a)
3/16,

 (b)
9/16,

 (c)
3/64,

 (d)
9/64,

 (e)
zero.
 7.

Given:
In
humans,
having
free
earlobes
is
dominant
to
having
 aCached
earlobes.

A
man
with
free
earlobes
marries
a
woman
with
 free
earlobes
and
they
have
a
child
with
aCached
earlobes.

If
they
 were
to
have
three
more
children,
the
chances
that
the
first
child
will
 have
free
earlobes,
the
second
will
have
aCached
earlobes,
and
the
 third
will
have
free
earlobes
are:
 (a)
3/16,

 (b)
9/16,

 (c)
3/64,

 (d)
9/64,

 (e)
zero.
 8.

Given:
In
foxes,
long
ears
(L)
is
dominant
to
short
ears
(l),
and
red
 fur
color
(R)
is
dominant
to
white
fur
color
(r).

These
genes
for
ear
 length
and
fur
color
are
located
on
different
autosomal
chromosomes.

 If
a
fox
that
is
homozygous
recessive
for
ear
length
and
homozygous
 dominant
for
fur
color
is
crossed
with
a
fox
that
is
homozygous
 recessive
for
both
characters:
 (a)
100%
of
the
offspring
will
have
long
ears
and
white
fur,
 (b)
100%
of
the
offspring
will
have
short
ears
and
red
fur,
 (c)
50%
of
the
offspring
will
have
long
ears
and
white
fur
and
50%
will
 have
short
ears
and
red
fur,
 (d)
50%
of
theoffspring
will
have
long
ears
and
red
fur
and
50%
will
 have
short
ears
and
white
fur,
 (e)
25%
of
the
offspring
will
have
long
ears
and
red
fur,
25%
will
have
 long
ears
and
white
fur,
25%
will
have
short
ears
and
red
fur,
and
25%
 will
have
short
ears
and
white
fur.

 8.

Given:
In
foxes,
long
ears
(L)
is
dominant
to
short
ears
(l),
and
red
 fur
color
(R)
is
dominant
to
white
fur
color
(r).

These
genes
for
ear
 length
and
fur
color
are
located
on
different
autosomal
chromosomes.

 If
a
fox
that
is
homozygous
recessive
for
ear
length
and
homozygous
 dominant
for
fur
color
is
crossed
with
a
fox
that
is
homozygous
 recessive
for
both
characters:
 (a)
100%
of
the
offspring
will
have
long
ears
and
white
fur,
 (b)
100%
of
the
offspring
will
have
short
ears
and
red
fur,
 (c)
50%
of
the
offspring
will
have
long
ears
and
white
fur
and
50%
will
 have
short
ears
and
red
fur,
 (d)
50%
of
the
offspring
will
have
long
ears
and
red
fur
and
50%
will
 have
short
ears
and
white
fur,
 (e)
25%
of
the
offspring
will
have
long
ears
and
red
fur,
25%
will
have
 long
ears
and
white
fur,
25%
will
have
short
ears
and
red
fur,
and
25%
 will
have
short
ears
and
white
fur.

 9.

Given:
In
Ipomoea
purpurea
plants,
purple
flower
color
(P)
is
dominant
to
white
 flower
color
(p),
and
heart‐shaped
leaf
(H)
is
dominant
to
oval‐shaped
leaf
(h).

 These
genes
for
flower
color
and
leaf
shape
are
located
on
different
autosomal
 chromosomes.

If
a
plant
that
is
heterozygous
for
both
characters
is
crossed
with
a
 plant
that
is
homozygous
dominant
for
flower
color
and
homozygous
recessive
for
 leaf
shape:
 (a)
100%
of
the
offspring
will
have
purple
flowers
and
heart‐shaped
leaves,
 (b)
100%
of
the
offspring
will
have
white
flowers
and
oval‐shaped
leaves,
 (c)
50%
of
the
offspring
will
have
purple
flowers
and
heart‐shaped
leaves
and
50%
 will
have
purple
flowers
and
oval‐shaped
leaves,
 (d)
50%
of
the
offspring
will
have
purple
flowers
and
heart‐shaped
leaves
and
50%
 will
have
white
flowers
and
oval‐shaped
leaves,
 (e)
25%
of
the
offspring
will
have
purple
flowers
and
heart‐shaped
leaves,
25%
will
 have
purple
flowers
and
oval‐shaped
leaves,
25%
will
have
white
flowers
and
heart‐ shaped
leaves,
and
25%
will
have
white
flowers
and
oval‐shaped
leaves.
 9.

Given:
In
Ipomoea
purpurea
plants,
purple
flower
color
(P)
is
dominant
to
white
 flower
color
(p),
and
heart‐shaped
leaf
(H)
is
dominant
to
oval‐shaped
leaf
(h).

 These
genes
for
flower
color
and
leaf
shape
are
located
on
different
autosomal
 chromosomes.

If
a
plant
that
is
heterozygous
for
both
characters
is
crossed
with
a
 plant
that
is
homozygous
dominant
for
flower
color
and
homozygous
recessive
for
 leaf
shape:
 (a)
100%
of
the
offspring
will
have
purple
flowers
and
heart‐shaped
leaves,
 (b)
100%
of
the
offspring
will
have
white
flowers
and
oval‐shaped
leaves,
 (c)
50%
of
the
offspring
will
have
purple
flowers
and
heart‐shaped
leaves
and
50%
 will
have
purple
flowers
and
oval‐shaped
leaves,
 (d)
50%of
the
offspring
will
have
purple
flowers
and
heart‐shaped
leaves
and
50%
 will
have
white
flowers
and
oval‐shaped
leaves,
 (e)
25%
of
the
offspring
will
have
purple
flowers
and
heart‐shaped
leaves,
25%
will
 have
purple
flowers
and
oval‐shaped
leaves,
25%
will
have
white
flowers
and
heart‐ shaped
leaves,
and
25%
will
have
white
flowers
and
oval‐shaped
leaves.
 10.

Given:
In
humans,
having
free
ear
lobes
(F)
is
dominant
to
having
 aCached
ear
lobes
(f),
and
being
able
to
roll
your
tongue
(T)
is
 dominant
to
not
being
able
to
roll
your
tongue
(t).

The
genes
that
 control
these
characters
are
on
different
autosomal
chromosomes.

If
 a
man
who
is
heterozygous
for
both
characters
marries
a
woman
who
 is
heterozygous
for
both
characters,
the
probability
that
they
will
have
 a
child
who
is
heterozygous
for
ear
lobes
and
homozygous
dominant
 for
tongue
rolling
is:
 (a)
zero
 (b)
.0625
 (c)
.125
 (d)
.25
 (e)
.5
 10.

Given:
In
humans,
having
free
ear
lobes
(F)
is
dominant
to
having
 aCached
ear
lobes
(f),
and
being
able
to
roll
your
tongue
(T)
is
 dominant
to
not
being
able
to
roll
your
tongue
(t).

The
genes
that
 control
these
characters
are
on
different
autosomal
chromosomes.

If
 a
man
who
is
heterozygous
for
both
characters
marries
a
woman
who
 is
heterozygous
for
both
characters,
the
probability
that
they
will
have
 a
child
who
is
heterozygous
for
ear
lobes
and
homozygous
dominant
 for
tongue
rolling
is:
 (a)
zero
 (b)
.0625
 (c)
.125
 (d)
.25
 (e)
.5
 11.

Given:
The
alleles
CR
and
CW.

A
rose
with
the
genotype
CRCR
has
 red
flowers,
a
rose
with
the
genotype
CWCW
has
white
flowers,
and
a
 rose
with
the
genotype
CRCW
has
pink
flowers.

This
is
an
example
of:

 (a)
synapsis,

 (b)
independent
assortment,

 (c)
complete
dominance,
 (d)
codominance,

 (e)
incomplete
dominance.
 11.

Given:
The
alleles
CR
and
CW.

A
rose
with
the
genotype
CRCR
has
 red
flowers,
a
rose
with
the
genotype
CWCW
has
white
flowers,
and
a
 rose
with
the
genotype
CRCW
has
pink
flowers.

This
is
an
example
of:

 (a)
synapsis,

 (b)
independent
assortment,

 (c)
complete
dominance,
 (d)
codominance,

 (e)
incomplete
dominance.
 12.

Given:
Cys;c
fibrosis,
which
occurs
in
individuals
who
are
 homozygous
for
the
pair
of
alleles
that
cause
it,
results
in
mul;ple
 phenotypic
effects.

This
is
an
example
of:

 (a)
mul;ple
alleles,

 (b)
epistasis,

 (c)
pleiotropy,
 (d)
polygenic
inheritance,

 (e)
linkage.
 12.

Given:
Cys;c
fibrosis,
which
occurs
in
individuals
who
are
 homozygous
for
the
pair
of
alleles
that
cause
it,
results
in
mul;ple
 phenotypic
effects.

This
is
an
example
of:

 (a)
mul;ple
alleles,

 (b)
epistasis,

 (c)
pleiotropy,
 (d)
polygenic
inheritance,

 (e)
linkage.
 13.

Given:
Men
and
women
have
an
equal
chance
of
having
Polycys;c
 Kidney
Disease,
and
any
person
who
carries
even
one
gene
for
this
 condi;on
will
have
Polycys;c
Kidney
Disease.

This
is
an
example
of
 a(n):

 (a)
autosomal
recessive
gene,

 (b)
autosomal
dominant
gene,

 (c)
X‐linked
recessive
gene,

 (d)
X‐linked
dominant
gene,
 (e)
Y‐linked
recessive
gene.
 13.

Given:
Men
and
women
have
an
equal
chance
of
having
Polycys;c
 Kidney
Disease,
and
any
person
who
carries
even
one
gene
for
this
 condi;on
will
have
Polycys;c
Kidney
Disease.

This
is
an
example
of
 a(n):

 (a)
autosomal
recessive
gene,

 (b)
autosomal
dominant
gene,

 (c)
X‐linked
recessive
gene,

 (d)
X‐linked
dominant
gene,
 (e)
Y‐linked
recessive
gene.
 14.

Given:

The
gene
for
knucklehead
disease
is
k
and
the
normal
 gene
is
k+.

The
gene
is
located
on
the
X
chromosome,
and
k+
is
 dominant
to
k.

A
woman
with
the
genotype
X
k+
Xk
marries
a
man
who
 has
the
genotype
Xk+
Y.

The
chances
that
they
will
have
a
child
who
 will
develop
knucklehead
disease
are:
 (a)
1/8,

 (b)
zero,

 (c)
1/2,

 (d)
1/4,

 (e)
1/1
(100%).
 14.

Given:

The
gene
for
knucklehead
disease
is
k
and
the
normal
 gene
is
k+.

The
gene
is
located
on
the
X
chromosome,
and
k+
is
 dominant
to
k.

A
woman
with
the
genotype
X
k+
Xk
marries
a
man
who
 has
the
genotype
Xk+
Y.

The
chances
that
they
will
have
a
child
who
 will
develop
knucklehead
disease
are:
 (a)
1/8,

 (b)
zero,

 (c)
1/2,

 (d)
1/4,

 (e)
1/1
(100%).
 15.

Given:

The
gene
for
knucklehead
disease
is
k
and
the
normal
 gene
is
k+.

The
gene
is
located
on
the
X
chromosome,
and
k+
is
 dominant
to
k.

A
woman
who
has
knucklehead
disease
marries
a
man
 who
is
normal
and
they
have
a
son.

The
chances
that
their
son
will
 have
knucklehead
disease
are:

 (a)
1/8,

 (b)
zero,

 (c)
1/2,

 (d)
1/4,

 (e)
1/1
(100%).
 15.

Given:

The
gene
for
knucklehead
disease
is
k
and
the
normal
 gene
is
k+.

The
gene
is
located
on
the
X
chromosome,
and
k+
is
 dominant
to
k.

A
woman
who
has
knucklehead
disease
marries
a
man
 who
is
normal
and
they
have
a
son.

The
chances
that
their
son
will
 have
knucklehead
disease
are:

 (a)
1/8,

 (b)
zero,

 (c)
1/2,

 (d)
1/4,

 (e)
1/1
(100%).
 16.

Given:
In
fruit
flies,
green
eye
color
(g)
is
recessive
to
normal
red
eye
color
(g+),
and
 knucklehead
(k)
is
recessive
to
normal
head
(k+).

The
genes
that
control
these
characters
are
 located
20
cen;morgans
(map
units)
from
one
another
on
the
same
autosomal
chromosome.

 A
male
fly
that
is
homozygous
recessive
for
both
characters
is
crossed
with
a
female
fly
that
is
 heterozygous
for
both
characters
such
that
g+
and
k
are
on
one
chromosome
and
g
and
k+
are
 on
the
homologous
chromosome.

If
they
produce
1000
offspring,
approximately:
 (a)
800
will
have
red
eyes
and
normal
heads
and
200
will
have
green
eyes
and
knuckleheads,

 (b)
800
will
have
red
eyes
and
knuckleheads
and
200
will
have
green
eyes
and
normal
heads,

 (c)
100
will
have
red
eyes
and
normal
heads,
100
will
have
green
eyes
and
knuckleheads,

 400
will
have
red
eyes
and
knuckleheads,
and
400
will
have
green
eyes
and
normal
heads,

 (d)
400
will
have
red
eyes
and
normal
heads,
400
will
have
green
eyes
and
knuckleheads,

 100
will
have
red
eyes
andknuckleheads,
and
100
will
have
green
eyes
and
normal
heads,

 (e)
250
will
have
red
eyes
and
normal
heads,
250
will
have
green
eyes
and
knuckleheads,

 250
will
have
red
eyes
and
knuckleheads,
and
250
will
have
green
eyes
and
normal
heads.
 16.

Given:
In
fruit
flies,
green
eye
color
(g)
is
recessive
to
normal
red
eye
color
(g+),
and
 knucklehead
(k)
is
recessive
to
normal
head
(k+).

The
genes
that
control
these
characters
are
 located
20
cen;morgans
(map
units)
from
one
another
on
the
same
autosomal
chromosome.

 A
male
fly
that
is
homozygous
recessive
for
both
characters
is
crossed
with
a
female
fly
that
is
 heterozygous
for
both
characters
such
that
g+
and
k
are
on
one
chromosome
and
g
and
k+
are
 on
the
homologous
chromosome.

If
they
produce
1000
offspring,
approximately:
 (a)
800
will
have
red
eyes
and
normal
heads
and
200
will
have
green
eyes
and
knuckleheads,

 (b)
800
will
have
red
eyes
and
knuckleheads
and
200
will
have
green
eyes
and
normal
heads,

 (c)
100
will
have
red
eyes
and
normal
heads,
100
will
have
green
eyes
and
knuckleheads,

 400
will
have
red
eyes
and
knuckleheads,
and
400
will
have
green
eyes
and
normal
heads,

 (d)
400
will
have
red
eyes
and
normal
heads,
400
will
have
green
eyes
and
knuckleheads,

 100
will
have
red
eyes
and
knuckleheads,
and
100
will
have
green
eyes
and
normal
heads,

 (e)
250
will
have
red
eyes
and
normal
heads,
250
will
have
green
eyes
and
knuckleheads,

 250
will
have
red
eyes
and
knuckleheads,
and
250
will
have
green
eyes
and
normal
heads.
 17.

Given:
Diploid
plants
having
a
chromosome
number
of
2n
=
28
 give
rise
to
autotetraploids.

The
autotetraploids
have
a
soma;c
 chromosome
number
of:
 (a)
56,

 (b)
42,

 (c)
35,

 (d)
28,

 (e)
21.
 17.

Given:
Diploid
plants
having
a
chromosome
number
of
2n
=
28
 give
rise
to
autotetraploids.

The
autotetraploids
have
a
soma;c
 chromosome
number
of:
 (a)
56,

 (b)
42,

 (c)
35,

 (d)
28,

 (e)
21.
 18.

Given:
Helenium
thurberi
has
a
chromosome
number
of
26,
 Helenium
bigelovii
has
a
chromosome
number
of
32,
and
Helenium
 puberulum
has
a
chromosome
number
of
58.

A
possible
explana;on
 for
the
chromosome
number
of
Helenium
puberulum
is
that
Helenium
 puberulum
is:
 (a)
an
autopolyploid
derived
from
Helenium
thurberi,

 (b)
an
autopolyploid
derived
from
Helenium
bigelovii,

 (c)
a
simple
allodiploid
derived
by
hybridiza;on
between
the
other
 two
species,

 (d)
an
allotetraploid
derived
by
hybridiza;on
and
chromosome
 doubling
from
the
other
two
species,

 (e)
a
triploid
derived
by
fusion
of
a
diploid
gamete
from
one
of
the
 other
species
and
a
haploid
gamete
from
the
other
species.
 18.

Given:
Helenium
thurberi
has
a
chromosome
number
of
26,
 Helenium
bigelovii
has
a
chromosome
number
of
32,
and
Helenium
 puberulum
has
a
chromosome
number
of
58.

A
possible
explana;on
 for
the
chromosome
number
of
Helenium
puberulum
is
that
Helenium
 puberulum
is:
 (a)
an
autopolyploid
derived
from
Helenium
thurberi,

 (b)
an
autopolyploid
derived
from
Helenium
bigelovii,

 (c)
a
simple
allodiploid
derived
by
hybridiza;on
between
the
other
 two
species,

 (d)
an
allotetraploid
derived
by
hybridiza*on
and
chromosome
 doubling
from
the
other
two
species,

 (e)
a
triploid
derived
by
fusion
of
a
diploid
gamete
from
one
of
the
 other
species
and
a
haploid
gamete
from
the
other
species.
 19.

A
gene;c
situa;on
that
involves
a
 major
altera;on
in
chromosome
structure
would
be:
 (a)
allopolyploidy,

 (b)
autopolyploidy,

 (c)
aneuploidy,
 
 
 
 
 
 
 
 
 
 
 
 (d)
transloca;on,

 (e)
epistasis.
 

 19.

A
gene;c
situa;on
that
involves
a
 major
altera;on
in
chromosome
structure
would
be:
 (a)
allopolyploidy,

 (b)
autopolyploidy,

 (c)
aneuploidy,
 
 
 
 
 



NOTE
 
 

 (d)
transloca*on,

 (e)
epistasis.
 20.

Trisomy
21
in
humans
results
in:
 (a)
Turner
Syndrome,

 (b)
Down
Syndrome,

 (c)
Klinefelter
Syndrome,

 (d)
Jacobs
Syndrome,

 (e)
Bierner
Syndrome.
 20.

Trisomy
21
in
humans
results
in:
 (a)
Turner
Syndrome,

 (b)
Down
Syndrome,

 (c)
Klinefelter
Syndrome,

 (d)
Jacobs
Syndrome,

 (e)
Bierner
Syndrome.
 Here’s
an
addi;onal
ques;on
having
to
do
with
a
trihybrid
cross.
 In
garden
peas,
yellow
pods
are
recessive
to
green
pods,
white
flowers
are
recessive
to
purple
flowers,
and
wrinkled
seeds
 are
recessive
to
round
seeds.

An
individual
that
was
heterozygous
for
all
three
characters
was
crossed
with
an
individual
 that
was
homozygous
recessive
for
all
three
with
the
following
results
among
the
offspring:
 2059 151 281 15 2041 157 282 11 
green
pods,
purple
flowers,
round
seeds
 
green
pods,
purple
flowers,
wrinkled
seeds
 
green
pods,
white
flowers,
round
seeds
 
green
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
round
seeds
 
yellow
pods,
purple
flowers,
wrinkled
seeds
 
yellow
pods,
purple
flowers,
round
seeds
 Here’s
an
addi;onal
ques;on
having
to
do
with
a
trihybrid
cross.
 In
garden
peas,
yellow
pods
are
recessive
to
green
pods,
white
flowers
are
recessive
to
purple
flowers,
and
wrinkled
seeds
 are
recessive
to
round
seeds.

An
individual
that
was
heterozygous
for
all
three
characters
was
crossed
with
an
individual
 that
was
homozygous
recessive
for
all
three
with
the
following
results
among
the
offspring:
 2059 151 281 15 2041 157 282 11 
green
pods,
purple
flowers,
round
seeds
 
green
pods,
purple
flowers,
wrinkled
seeds
 
green
pods,
white
flowers,
round
seeds
 
green
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
round
seeds
 
yellow
pods,
purple
flowers,
wrinkled
seeds
 
yellow
pods,
purple
flowers,
round
seeds
 How
were
the
genes
arranged
on
the
chromosomes
of
the
individual
that
was
heterozygous
for
all
three
characters?


 Here’s
an
addi;onal
ques;on
having
to
do
with
a
trihybrid
cross.
 In
garden
peas,
yellow
pods
are
recessive
to
green
pods,
white
flowers
are
recessive
to
purple
flowers,
and
wrinkled
seeds
 are
recessive
to
round
seeds.

An
individual
that
was
heterozygous
for
all
three
characters
was
crossed
with
an
individual
 that
washomozygous
recessive
for
all
three
with
the
following
results
among
the
offspring:
 2059 151 281 15 2041 157 282 11 
green
pods,
purple
flowers,
round
seeds
 
green
pods,
purple
flowers,
wrinkled
seeds
 
green
pods,
white
flowers,
round
seeds
 
green
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
round
seeds
 
yellow
pods,
purple
flowers,
wrinkled
seeds
 
yellow
pods,
purple
flowers,
round
seeds
 How
were
the
genes
arranged
on
the
chromosomes
of
the
individual
that
was
heterozygous
for
all
three
characters?


 All
of
the
dominant
alleles
were
on
one
chromosome,
and
all
of
the
recessive
alleles
were
on
the
homologous
 chromosome.
 Here’s
an
addi;onal
ques;on
having
to
do
with
a
trihybrid
cross.
 In
garden
peas,
yellow
pods
are
recessive
to
green
pods,
white
flowers
are
recessive
to
purple
flowers,
and
wrinkled
seeds
 are
recessive
to
round
seeds.

An
individual
that
was
heterozygous
for
all
three
characters
was
crossed
with
an
individual
 that
was
homozygous
recessive
for
all
three
with
the
following
results
among
the
offspring:
 2059 151 281 15 2041 157 282 11 
green
pods,
purple
flowers,
round
seeds
 
green
pods,
purple
flowers,
wrinkled
seeds
 
green
pods,
white
flowers,
round
seeds
 
green
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
round
seeds
 
yellow
pods,
purple
flowers,
wrinkled
seeds
 
yellow
pods,
purple
flowers,
round
seeds
 How
were
the
genes
arranged
on
the
chromosomes
of
the
individual
that
was
heterozygous
for
all
three
characters?


 All
of
the
dominant
alleles
were
on
one
chromosome,
and
all
of
the
recessive
alleles
were
on
the
homologous
 chromosome.
 Which
gene
is
in
the
middle?


 Here’s
an
addi;onal
ques;on
having
to
do
with
a
trihybrid
cross.
 In
garden
peas,
yellow
pods
are
recessive
to
green
pods,
white
flowers
are
recessive
to
purple
flowers,
and
wrinkled
seeds
 are
recessive
to
round
seeds.

An
individual
that
was
heterozygous
for
all
three
characters
was
crossed
with
an
individual
 that
was
homozygous
recessive
for
all
three
with
the
following
results
among
the
offspring:
 2059 151 281 15 2041 157 282 11 
green
pods,
purple
flowers,
round
seeds
 
green
pods,
purple
flowers,
wrinkled
seeds
 
green
pods,
white
flowers,
round
seeds
 
green
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
round
seeds
 
yellow
pods,
purple
flowers,
wrinkled
seeds
 
yellow
pods,
purple
flowers,
round
seeds
 How
were
the
genes
arranged
on
the
chromosomes
of
the
individual
that
was
heterozygous
for
all
three
characters?


 All
of
the
dominant
alleles
were
on
one
chromosome,
and
all
of
the
recessive
alleles
were
on
the
homologous
 chromosome.
 Which
gene
is
in
the
middle?


 The
gene
for
pod
color.
 Here’s
an
addi;onal
ques;on
having
to
do
with
a
trihybrid
cross.
 In
garden
peas,
yellow
pods
are
recessive
to
green
pods,
white
flowers
are
recessive
to
purple
flowers,
and
wrinkled
seeds
 are
recessive
to
round
seeds.

An
individual
that
was
heterozygous
for
all
three
characters
was
crossed
with
an
individual
 that
was
homozygous
recessive
for
all
three
with
the
following
results
among
the
offspring:
 2059 151 281 15 2041 157 282 11 
green
pods,
purple
flowers,
round
seeds
 
green
pods,
purple
flowers,
wrinkled
seeds
 
green
pods,
white
flowers,
round
seeds
 
green
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
round
seeds
 
yellow
pods,
purple
flowers,
wrinkled
seeds
 
yellow
pods,
purple
flowers,
round
seeds
 How
were
the
genes
arranged
on
the
chromosomes
of
the
individual
that
was
heterozygous
for
all
three
characters?


 All
of
the
dominant
alleles
were
on
one
chromosome,
and
all
of
the
recessive
alleles
were
on
the
homologous
 chromosome.
 Which
gene
is
in
the
middle?


 The
gene
for
pod
color.
Note:
you
have
to
compare
each
double
crossover
with
the
parental
type
from
which
it
 differs
by
only
one
phenotypic
trait.


 Here’s
an
addi;onal
ques;on
having
to
do
with
a
trihybrid
cross.
 In
garden
peas,
yellow
pods
are
recessive
to
green
pods,
white
flowers
are
recessive
to
purple
flowers,
and
wrinkled
seeds
 are
recessive
to
round
seeds.

An
individual
that
was
heterozygous
for
all
three
characters
was
crossed
with
an
individual
 that
was
homozygous
recessive
for
all
three
with
the
following
results
among
the
offspring:
 2059 151 281 15 2041 157 282 11 
green
pods,
purple
flowers,
round
seeds
 
green
pods,
purple
flowers,
wrinkled
seeds
 
green
pods,
white
flowers,
round
seeds
 
green
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
round
seeds
 
yellow
pods,
purple
flowers,
wrinkled
seeds
 
yellow
pods,
purple
flowers,
round
seeds
 How
were
the
genes
arranged
on
the
chromosomes
of
the
individual
that
was
heterozygous
for
all
three
characters?


 All
of
the
dominant
alleles
were
on
one
chromosome,
and
all
of
the
recessive
alleles
were
on
the
homologous
 chromosome.
 Which
gene
is
in
the
middle?


 The
gene
for
pod
color.
Note:
you
have
to
compare
each
double
crossover
with
the
parental
type
from
which
it
 differs
by
only
one
phenotypic
trait.


 yellow/purple/round
against
green/purple/round
 Here’s
an
addi;onal
ques;on
having
to
do
with
a
trihybrid
cross.
 In
garden
peas,
yellow
pods
are
recessive
to
green
pods,
white
flowers
are
recessive
to
purple
flowers,
and
wrinkled
seeds
 are
recessive
to
round
seeds.

An
individual
that
was
heterozygous
for
all
three
characters
was
crossed
with
an
individual
 that
was
homozygous
recessive
for
all
three
with
the
following
results
among
the
offspring:
 2059 151 281 15 2041 157 282 11 
green
pods,
purple
flowers,
round
seeds
 
green
pods,
purple
flowers,
wrinkled
seeds
 
green
pods,
white
flowers,
round
seeds
 
green
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
round
seeds
 
yellow
pods,
purple
flowers,
wrinkled
seeds
 
yellow
pods,
purple
flowers,
round
seeds
 How
were
the
genes
arranged
on
the
chromosomesof
the
individual
that
was
heterozygous
for
all
three
characters?


 All
of
the
dominant
alleles
were
on
one
chromosome,
and
all
of
the
recessive
alleles
were
on
the
homologous
 chromosome.
 Which
gene
is
in
the
middle?


 The
gene
for
pod
color.
Note:
you
have
to
compare
each
double
crossover
with
the
parental
type
from
which
it
 differs
by
only
one
phenotypic
trait.

 green/white/wrinkled
against
yellow/white/wrinkled
 Here’s
an
addi;onal
ques;on
having
to
do
with
a
trihybrid
cross.
 In
garden
peas,
yellow
pods
are
recessive
to
green
pods,
white
flowers
are
recessive
to
purple
flowers,
and
wrinkled
seeds
 are
recessive
to
round
seeds.

An
individual
that
was
heterozygous
for
all
three
characters
was
crossed
with
an
individual
 that
was
homozygous
recessive
for
all
three
with
the
following
results
among
the
offspring:
 2059 151 281 15 2041 157 282 11 
green
pods,
purple
flowers,
round
seeds
 
green
pods,
purple
flowers,
wrinkled
seeds
 
green
pods,
white
flowers,
round
seeds
 
green
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
round
seeds
 
yellow
pods,
purple
flowers,
wrinkled
seeds
 
yellow
pods,
purple
flowers,
round
seeds
 How
were
the
genes
arranged
on
the
chromosomes
of
the
individual
that
was
heterozygous
for
all
three
characters?


 All
of
the
dominant
alleles
were
on
one
chromosome,
and
all
of
the
recessive
alleles
were
on
the
homologous
 chromosome.
 Which
gene
is
in
the
middle?


 The
gene
for
pod
color.
Note:
you
have
to
compare
each
double
crossover
with
the
parental
type
from
which
it
 differs
by
only
one
phenotypic
trait.

 Pod
color
is
the
odd
gene
out.
 Here’s
an
addi;onal
ques;on
having
to
do
with
a
trihybrid
cross.
 In
garden
peas,
yellow
pods
are
recessive
to
green
pods,
white
flowers
are
recessive
to
purple
flowers,
and
wrinkled
seeds
 are
recessive
to
round
seeds.

An
individual
that
was
heterozygous
for
all
three
characters
was
crossed
with
an
individual
 that
was
homozygous
recessive
for
all
three
with
the
following
results
among
the
offspring:
 2059 151 281 15 2041 157 282 11 
green
pods,
purple
flowers,
round
seeds
 
green
pods,
purple
flowers,
wrinkled
seeds
 
green
pods,
white
flowers,
round
seeds
 
green
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
round
seeds
 
yellow
pods,
purple
flowers,
wrinkled
seeds
 
yellow
pods,
purple
flowers,
round
seeds
 How
were
the
genes
arranged
on
the
chromosomes
of
the
individual
that
was
heterozygous
for
all
three
characters?


 All
of
the
dominant
alleles
were
on
one
chromosome,
and
all
of
the
recessive
alleles
were
on
the
homologous
 chromosome.
 Which
gene
is
in
the
middle?


 The
gene
for
pod
color.
 What
are
the
map
unit
distances
among
the
three
genes?


 Here’s
an
addi;onal
ques;on
having
to
do
with
a
trihybrid
cross.
 In
garden
peas,
yellow
pods
are
recessive
to
green
pods,
white
flowers
are
recessive
to
purple
flowers,
and
wrinkled
seeds
 are
recessive
to
round
seeds.

An
individual
that
was
heterozygous
for
all
three
characters
was
crossed
with
an
individual
 that
was
homozygous
recessive
for
all
three
with
the
following
results
among
the
offspring:
 2059 151 281 15 2041 157 282 11 
green
pods,
purple
flowers,
round
seeds
 
green
pods,
purple
flowers,
wrinkled
seeds
 
green
pods,
white
flowers,
round
seeds
 
green
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
round
seeds
 
yellow
pods,
purple
flowers,
wrinkled
seeds
 
yellow
pods,
purple
flowers,
round
seeds
 How
were
the
genes
arranged
on
the
chromosomes
of
the
individual
that
was
heterozygous
for
all
three
characters?


 All
of
the
dominant
alleles
were
on
one
chromosome,
and
all
of
the
recessive
alleles
were
on
the
homologous
 chromosome.
 Which
gene
is
in
the
middle?


 The
gene
for
pod
color.
 What
are
the
map
unit
distances
among
the
three
genes?


 Pod
color
gene
to
flower
color
gene
is
11.8
map
units
 Here’s
an
addi;onal
ques;on
having
to
do
with
a
trihybrid
cross.
 In
garden
peas,
yellow
pods
are
recessive
to
green
pods,
white
flowers
are
recessive
to
purple
flowers,
and
wrinkled
seeds
 are
recessive
to
round
seeds.

An
individual
that
was
heterozygous
for
all
three
characters
was
crossed
with
an
individual
 that
was
homozygous
recessive
for
all
three
with
the
following
results
among
the
offspring:
 2059 151 281 15 2041 157 282 11 
green
pods,
purple
flowers,
round
seeds
 
green
pods,
purple
flowers,
wrinkled
seeds
 
green
pods,
white
flowers,
round
seeds
 
green
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
round
seeds
 
yellow
pods,
purple
flowers,
wrinkled
seeds
 
yellow
pods,
purple
flowers,
round
seeds
 How
were
the
genes
arranged
on
the
chromosomes
of
the
individual
that
was
heterozygous
for
all
three
characters?


 All
of
the
dominant
alleles
were
on
one
chromosome,
and
all
of
the
recessive
alleles
were
on
the
homologous
 chromosome.
 Which
gene
is
in
the
middle?


 The
gene
for
pod
color.
 What
are
the
map
unit
distances
among
the
three
genes?


 Pod
color
gene
to
flower
color
gene
is
11.8
map
units
 Pod
color
gene
to
seed
shape
gene
is
6.7
map
units
 Here’s
an
addi;onal
ques;on
having
to
do
with
a
trihybrid
cross.
 In
garden
peas,
yellow
pods
are
recessive
to
green
pods,
white
flowers
are
recessive
to
purple
flowers,
and
wrinkled
seeds
 are
recessive
to
round
seeds.

An
individual
that
was
heterozygous
for
all
three
characters
was
crossed
with
an
individual
 that
was
homozygous
recessive
for
all
three
with
the
following
results
among
the
offspring:
 2059 151 281 15 2041 157 282 11 
green
pods,
purple
flowers,
round
seeds
 
green
pods,
purple
flowers,
wrinkled
seeds
 
green
pods,
white
flowers,
round
seeds
 
green
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
wrinkled
seeds
 
yellow
pods,
white
flowers,
round
seeds
 
yellow
pods,
purple
flowers,
wrinkled
seeds
 
yellow
pods,
purple
flowers,
round
seeds
 How
were
the
genes
arranged
on
the
chromosomes
of
the
individual
that
washeterozygous
for
all
three
characters?


 All
of
the
dominant
alleles
were
on
one
chromosome,
and
all
of
the
recessive
alleles
were
on
the
homologous
 chromosome.
 Which
gene
is
in
the
middle?


 The
gene
for
pod
color.
 What
are
the
map
unit
distances
among
the
three
genes?


 Pod
color
gene
to
flower
color
gene
is
11.8
map
units
 Pod
color
gene
to
seed
shape
gene
is
6.7
map
units
 Flower
color
gene
to
seed
shape
gene
is
18.5
map
units
(Don’t
forget
the
double
crossovers
*mes
2)
 ...
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This note was uploaded on 10/24/2011 for the course BIO 325 taught by Professor Saxena during the Spring '08 term at University of Texas at Austin.

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