HW_Problem_4_solution

# HW_Problem_4_solution - HW_Problems_4_soln 1 = 4.45 1017 cm...

This preview shows page 1. Sign up to view the full content.

HW_Problems_4_soln 1. 17 3 4.45 10 C N cm = × 18 3 7.72 10 For GaAs at 300k V N cm = × 17 17 17 17 17 17 10 Boltzmann: ln( ) (0.026)ln 4.45 10 0.039 10 10 J-D: ln( ) (0.026)[ln ] 4.45 10 8(4.45 10 ) 0. Fn C C C C Fn C C C C n E E kT E eV N E eV n E E kT E eV N E = + = + × = = + = + + × × = 037 eV 17 18 10 For holes: ln( ) 0.113 7.72 10 Fp V V E E kT E eV = = + × 2. (1). The drift velocity is 2 15 (1300 / )(100 / ) 1.3 10 / d v E cm vs v cm cm s µ = = = × The excess energy is * 2 31 3 1 1 (0.26 9.1 10 )(1.3 10 / ) 2 2 d E m v kg m s = = × × 25 6 2.0 10 1.25 10 J eV = × = × (2). This energy is relatively small compared to the electron thermal energy: 3 3 at 300k: 39 2 2 th kT E kT meV = = (3). At 5KV/cm, the drift velocity is: 3 6 (1300)(5 10 ) 6.5 10 / d v cm s = × = × The excess energy is
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern