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Unformatted text preview: 0.9319727891 a 0.01 a/2 0.005 1-a/2 0.995 normsinv(1-a/2) 2.5758293035 p.hat (z)* sqrt(p.hat*((1-p.hat)/n) total/answer low 0.9319727891 0.0308845113 0.901088 high 0.9319727891 0.0308845113 0.962857 NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6 in an earlier study, the population proportion was estimater to be 0.22 how large a sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 98 % confidence level with an error at most 0.02 confidence level or 1-a 0.98 sample porption or p.hat 0.22 allowable error 0.02 a 0.02 a/2 0.01 1-a/2 0.99 normsinv(1-a/2) 2.326347874 n= 5.4118944311 0.1716 0.0004 2321.70271092 did not have spills % confidence interval for the proportion of oil tankers that have spills each month were defective . were defective . % confidence interval for the proportion of disks which are defective...
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This document was uploaded on 10/26/2011 for the course QMST 2333 at Texas State.
- Fall '08