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Unformatted text preview: -1 mol-1 = 0.08206 L atm K-1 mol-1 Plancks constant h = 6.626 x 10-34 J s Speed of light c = 2.998 x 10 8 m s-1 Rydbergs constant R H = 2.1798 x 10-18 J Zero point 0C = 273.15 K = 3.1415927 Conversion Factors: 1 atm = 1.01325 x 10 5 Pa (N m-2 ) = 760.0 mmHg (torr) = 1.01325 bar J = kg m 2 s-2 1 cal = 4.8184 J Equations: E = h = h c/ matter = h /mc c= (R= 1.097 x 10-2 nm-1 ) M 1 V 1 = M 2 V 2 PV = nRT P tot = P 1 + P 2 + P 3 + P A = X A P tot P soln = P solv X solv = MRT Dipole moment, = Q x r T b = K b m T f = -K f m w = -PV E = q + w H = E + PV G = H - TS G = G + RT ln Q CHEM 1010 Name:___________________________________ Student ID_____________...
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This note was uploaded on 10/25/2011 for the course CHEM 1010 taught by Professor Olga during the Spring '11 term at UOIT.
- Spring '11