Sol_ELCT_371_Homework1_Sp11

Sol_ELCT_371_Homework1_Sp11 - ELCT 371: Spring 2011...

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ELCT 371: Spring 2011 Homework #1 solution Problem 1 50 = + = = O L L vo o R R R A Vi V Av 40 250 200 * 50 = = + + = = K K Rs Ri R R R R A Vs V Avs i O L L vo o 6 3 10 * 5 . 2 4 / 10 * 200 * 50 = = = L i R R Av Ai 8 10 25 . 1 = = AvAi G Problem 2 Using the unity-gain amplifier we have: 100 Ohm 1M 5V Vi 50 Ohm 200K 2 mV 100 Vi 4 Ohm 4 Ohm 200K 50K V Rs Ri R R R R Vs Vo i O L L 38 . 1 1200000 / 1000000 * ) 100 50 /( 50 * 5 = + = + + = 1
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mW R V Po L o 1 . 38 / 2 = = With the source connected directly to the load, we have : 2 mV Rs R R Vs Vo L L 25 . 1 ) 200000 50 /( 50 * 5 = + = + = nW R V Po L o 2 . 31 / 2 = = Thus the output power is much larger if the unity- gain amplifier is used. Problem 3 Ri 100Vi 200K 50 Ohm 5V 10K 4 4 10 10 100 80 + = + = = Ro Ro R R Avo Av L L Solving we find that Ro = 2.5 Ω K Problem 4 With the switch open we have : Ro R R Avo R R Vs mV Vo L L i i + + = = 6 10 50 ………….(1)
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With the switch closed we have: Ro R R Avo Vs mV Vo L L + = = * 100 ………………….(2)
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Sol_ELCT_371_Homework1_Sp11 - ELCT 371: Spring 2011...

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