C serve as recombinant dna vectors d map genes and

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: iduals have two or more incomplete sets of chromosomes. PRE MED 411 .CO MPRE M ED4 11. A.True B.False Answer: B M .CO 411 MED - PR E - PR EME D41 1.C OM - PR EME D41 1.C OM 27. Bacterial mutants that require additional nutrients in their growth media are called _________. A. wild type bacteria cells B. cultured bacteria cells C. auxotrophs D. prototrophs E. recombinant bacterial cells Answer: C - PR EME D41 1.C OM - PR EME D41 1.C OM 28. Bacterial cells containing an F plasmid that has acquired bacterial chromosomal genes are called A. F+ B. F’ C. F_ D. Hfr Answer: B - PR EME D41 1.C OM - PR EME D41 1.C OM 29. leu– bacteria are mixed in a flask with leu+ bacteria, and soon all bacteria are leu+. However, if the leu– cells are on one side of a U-tube and the leu+ cells are on the other, the leu– cells do not become prototrophic. This suggests A. conjugation. B. transduction. C. transformation. D. recombination. Answer: A PRE MED 411 .CO MPRE M ED4 11. COM - PR EME D4 11. COM - PR EME D4 11. COM - PR EME D41 1.C OM - PR EME D41 1.C OM 30. A section of a genome is cut with three enzymes: A, B, and C. Cutting with A and B yields a 10-kb fragment. Cutting with B and C yields a 2-kb fragment. What is the expected result from a digest with A and C, if the C site lies in between the A and B sites? A. a 12-kb fragment B. an 8-kb fragment C. an 8-kb and a 2-kb fragment D. a 10-kb and a 2-kb fragment E. a 10-kb, an 8-kb, and a 2-kb fragment Answer: B M .CO 411 MED - PR E OM D41 1.C Extra credit question (1 point): D41 1.C OM - PR EME D41 1.C OM - PR EME 31. A news article published in “Nature” on 10 November 2004 reported a new way to lower cholesterol using RNA Interference technique. This article is also available at the Blackboard site, chapter 18 folder. In the past, scientists often had difficulties to deliver the treatment to the right part of the patient’s body. According to this report, researchers from Germany and the U.S. have figured out a way to solve the problem, at least for treating high cholesterol. They modified the RNA molecule used to trigger the interference by attaching a cholesterol molecule to it. This is because: OM - PR EME a) Cells that make cholesterol have no cholesterol antibodies on their surface, so that the modified RNA complex can be taken up by these particular cells in the right body part. - PR EME D41 1.C b) Cells that make cholesterol have no cholesterol receptors on their surface, so that the modified RNA complex can be taken up by these particular cells in the right body part. - PR EME D41 1.C OM c) Cells that make cholesterol have cholesterol receptors on their surface, so that the modified RNA complex can be taken up by these particular cells in the right body part. - PR EME D41 1.C OM d) Cells that make cholesterol have cholesterol antibodies on their surface, so that the modified RNA complex can be rejected by these particular cells in the right body part. OM e) None of the above is correct. PRE MED 411 .CO MPRE M ED4 11. COM - PR EME D4 11. COM - PR EME D4 11. COM - PR EME D41 1.C OM - PR EME D41 1.C Answer Key: C...
View Full Document

This document was uploaded on 10/27/2011 for the course BIL 250 at University of Miami.

Ask a homework question - tutors are online