report1 - Solution of Laplaces Equation by Finite...

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Solution of Laplace’s Equation by Finite Differences By: Carlos Moran PS Number: 0429409 For: ECE 2317: Applied Electricity and Magnetism (Fall 2007) Instructor: Ji Chen
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Task 1 Task 1 required to find the potential on each node inside of the box. To perform this task I had to find the average of the four adjacent points. Once I performed this action, the node would be updated and then it would be used for the average of the next point. As you can see on the data, as we distance from the strip the potential tends to decrease. Below is the table to the values of the volts on the row containing the strip. For N=4 1 0 14 0.35532 27 1 40 0.13856 2 0.0095346 15 0.46908 28 1 41 0.11104 3 0.01941 16 0.65012 29 1 42 0.088757 4 0.029986 17 1 30 1 43 0.070386 5 0.041671 18 1 31 1 44 0.054941 6 0.054941 19 1 32 1 45 0.041671 7 0.070386 20 1 33 1 46 0.029986 8 0.088757 21 1 34 0.65012 47 0.01941 9 0.11104 22 1 35 0.46908 48 0.009535 10 0.13856 23 1 36 0.35532 49 0 11 0.1732 24 1 37 0.27603 12 0.21764 25 1 38 0.21764 13 0.27603 26 1 39 0.1732 For N=1 1 0 2 0.056538 3 0.15225 4 0.37474 5 1 6 1 7 1 8 1 9 1 10 0.37474 11 0.15225 12 0.056538 13 0 For N=2 1 0 14 1 2 0.021095 15 1 3 0.045344 16 1 4 0.076757 17 1 5 0.1215 18 0.52253 6 0.19052 19 0.3062 7 0.3062 20 0.19052 8 0.52253 21 0.1215 9 1 22 0.076757 10 1 23 0.045344 11 1 24 0.021095 12 1 25 0 13 1
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This note was uploaded on 10/25/2011 for the course ECE 2317 taught by Professor Staff during the Fall '08 term at University of Houston.

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report1 - Solution of Laplaces Equation by Finite...

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