Homework Sol Due 9-12-2011

Homework Sol Due 9-12-2011 - ISEN 620 Homework Solutions...

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ISEN 620 Homework Solutions Due 9-12-2011 Consider the matrix A : 130 21 1 392 A ⎡⎤ ⎢⎥ =− ⎣⎦ 1. Using the following ERO what is the result on A ? 12 2 13 3 2 3 Row Row Row Row Row Row +→ −+ 07 1 002 ERO −− →− 2. Using the result from 1, continue with ERO’s, what is the resultant A’ ? 22 33 1/7 1/2 Row Row Row Row 13 0 01 1 / 7 00 1 ERO ERO 3. Assume that we have the system of equations ( ) ,4 0 1 0 T Ax b b == . Apply the following ERO’s to solve this system. What is the solution? 2 3 2 3 Row Row Row Row Row Row Row Row Row Row Applied to A we get the matrix answer of problem 2 above. Applied to the rhs () 48 / 7 1 T b , and using backward substitution we obtain 11 1 T x .
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4. Using the augmented matrix approach with ERO’s to obtain the inverse of A : 12 2 13 3 22 33 130100 21 1010 392001 using ERO's of 2 and -3 13 0 1 00 07 1 2 10 00 2 301 using ERO's of 1/7 and 1/ 2 13 0 1 0 0 01 1 / 7 2 / 7 1 / 7 0 0 0 1
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This note was uploaded on 10/26/2011 for the course ISEN 620 taught by Professor Curry during the Fall '10 term at Texas A&M.

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Homework Sol Due 9-12-2011 - ISEN 620 Homework Solutions...

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