MAT101- MOD2 - Case 2 - MOD2 - New

MAT101- MOD2 - Case 2 - MOD2 - New - RodneyBuckmire

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Rodney Buckmire MAT101 – Module 2 – Case Assignment Dr. Schek Part 1:  1. X= daily fee y= mileage 3x + 300y=123 5x +600y=216 15x + 1500y=615 -15 – 1800y= 648 -300y=-33 y=33/-300 = 0.11(y=.11 cents per mile) 3x + 300(.11) = 123 3x + 33 + 123 3x = 90 x = 30(daily fee) So, daily fee $30 and .11 cents per miles.  2. X+y= 44,000 (total attended) 13x + 6y = 369,000 (total income) y= 29,000(general)   x= 15,000(reserved) 3. X+3y=32 -3x+2y=3 3x+9y=96; -3x+2y=3; 11y=99 then y=9 x=32-3y; x=32-3*9; x=32-27=x=5 (5,9) 4. X=y=5 x-y=-9 2x=-4; x=-2
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y=5-x; y=5=2; y=7 (-2, 7) 5. X=(52-x) + 12 x+x=52+12 2x=64 x=62/2 x=32(games won)
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Part 2: Question 1 - Draw the graphs of 2x-y-1 = 0 and 2x + y = 9; Write down the co-ordinates of the point of intersection of the  two lines. 5 4 3 2 1 -5 -4 -3 -2 -1 0 1 2 3 4 -1 -2 -3 -4 (2.5, 4)
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two lines. 5
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This note was uploaded on 10/26/2011 for the course MAT 101 taught by Professor Choi during the Fall '11 term at Trident Technical College.

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MAT101- MOD2 - Case 2 - MOD2 - New - RodneyBuckmire

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