Unformatted text preview: Let the cost of the first car part be x and that of the second be y. Selling price of the first = cost price + profit = x + 0.25x = 1.25x Selling price of the second = cost price + profit = y + 0.10y = 1.10y Total revenue = 1.25x + 1.10y = 1520 ⇒ y = (1520 – 1.25x)/1.10  (1) Similarly in the retailer case, 1.10x + 1.25y = 1535  (2) Plug this in place of y in (2) then we get 1.10x + 1.25[(1520 – 1.25x)/1.10] = 1535 1.10x + 1727.27 – 1.42x = 1535 On solving we get x = $600 and y = [1520 – 1.25 × 600]/1.10 = $700. Solution: (x, y) = ($600, $700) The costs of the two car parts were $500 and $700 This system is consistent and independent. It has a unique solution....
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This note was uploaded on 10/26/2011 for the course MAT 101 taught by Professor Choi during the Fall '11 term at Trident Technical College.
 Fall '11
 Choi
 Math

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