{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

s3a10 - Solutions Homework 3a09 Physics E-1a Fall 2010 MC 1...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Physics E-1a Solutions Homework 3a09 Fall 2010 MC 1 A nswer b) is False). From Newton's third law for every action there is an equal and opposite action. Pulling on the handle causes a force to be applied to the block which and gives rise to a tension in the string. The tension in the string acts on the ball and the ball acts back on the string. MC 2 The answer is d) The acceleration along the plane depends only on the angle of the incline and the acceleration due to gravity (the value of g). MC 3 The answer is a). We refer to Newton’s second law: ma = F net . The problem statement indicates that force is constant. The graphs show acceleration as a function of mass, so we rearrange the equation to read m F a net = . This is an inverse relationship, as shown in graph (a). Note that (c) is not correct: for greater masses than those shown, the acceleration would become negative. MC 4 The answer is d) the angle depends on the coefficient of friction F x = F fr or mg sin ! = μ F N with F N = mg cos ! gives mg sin ! = μ mg cos ! then μ = tan ! 30. Find the net force on the elevator; and from it determine the acceleration. Then use Eq. (4-5) to find the speed . Find the net force on the elevator .
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern