s6a11 - Physics E-1a Homework Assignment#6 Solutions Fall...

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Physics E-1a Homework Assignment #6 Solutions Fall 2011 1. a) We solve this problem with the momentum form of Newton’s second law. F ! = " p " t , where ! p = m ! v = 1.50kg ( ) 0 " ( ) = " 6N # s Then F = ! " s 2.5 # 10 ! 3 s = ! 2400N b) No. There would be no difference in the force if the hands have same initial velocity as in part a) and stop in the same time, Δ t. The change in momentum and the interaction time are the same for both collisions, therefore the force is the same. 2. a) The impulse imparted by the blow is, F ! t = 1000N ( ) 0.15s ( ) = 150N " s b) We find the opponents final velocity from his change in momentum. F ! t = m ! v " so ! v = impulse mass = 150N # s 105kg = 1.43m s 3. The force of the paint chip is equal to the change in momentum of the chip divided by the duration of the collision. F = ! p ! t = m ! v ! t = 0.100 " 10 # 6 kg ( ) 4.00 " 10 3 # 0 ( ) m s 6.00 " 10 # 8 s = 6.67 " 10 3 N 4. First, we find the change in momentum from the applied force and the duration of the collision, then find the mass of the ball as we know its final velocity.
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This note was uploaded on 10/26/2011 for the course PHYSICS E-1a taught by Professor Wolfgangrueckner during the Fall '11 term at Harvard.

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s6a11 - Physics E-1a Homework Assignment#6 Solutions Fall...

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