General 1-D motion •Average velocity: 21avexxxtttυ−Δ==Δ−•Average acceleration: aveattt−Δ•Instantaneous velocity: dxdt=•Instantaneous acceleration: 22ddadtdtx0Example 1. Particles Aand Bare moving along a straight line. Their positions are defined as m and m for s. 321.5102040Axttt=−++−432(1/ 6)(8 / 3)51510Bxtttt=−−++01t≤≤(a) At what time instant do these two particles have the same acceleration? Ans: t= 6 s (b) Calculate the average acceleration of Aduring the interval between t= 2 s and t= 6 s. Ans: −16 m/s22. The position of a particle moving along a straight line is given by m for the duration of s. ()640ttt=− − +08t(a) Draw the , , and xttat−−−graphs. x–t
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This note was uploaded on 04/06/2008 for the course PHYS 2305 taught by Professor Tschang during the Fall '08 term at Virginia Tech.