General 1-D motion •Average velocity: 2121avexxxtttυ−Δ==Δ−•Average acceleration: 2121aveatttυυυ−Δ==Δ−•Instantaneous velocity: dxdtυ=•Instantaneous acceleration: 22ddadtdtυ==x0Example 1. Particles Aand Bare moving along a straight line. Their positions are defined as m and m for s. 321.5102040Axttt= −++−432(1/6)(8/3)51510Bxtttt=−−++01t≤≤(a) At what time instant do these two particles have the same acceleration? Ans: t= 6 s (b) Calculate the average acceleration of Aduring the interval between t= 2 s and t= 6 s. Ans: −16 m/s22. The position of a particle moving along a straight line is given by m for the duration of s. 32( )61540x tttt=−−+08t≤≤(a) Draw the , , and xttat
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