Chapter 10 Practice - Rotational Kinematics-solutions

Chapter 10 Practice - Rotational Kinematics-solutions -...

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kaplan (hmk378) – Chapter 10 Practice - Rotational Kinematics – Weathers – (17104) 1 This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. This problem set is NOT for credit; it is practice/review for Exam 2 001 10.0 points A girl sitting on a merry-go-round moves counterclockwise through an arc length of 3.40 m. If the girl’s angular displacement is 1.13 rad, how far is she from the center of the merry-go-round? Correct answer: 3 . 00885 m. Explanation: Let : Δ s = 3 . 40 m and Δ θ = 1 . 13 rad . Δ s = r Δ θ r = Δ s Δ θ = 3 . 4 m 1 . 13 rad = 3 . 00885 m . keywords: 002 10.0 points A car tire rotates with an average angular speed of 29 rad/s. In what time interval will the tire rotate 3 . 4 times? Correct answer: 0 . 736649 s. Explanation: Let : ω avg = 29 rad / s and Δ θ = 3 . 4 rev . ω avg = Δ θ Δ t Δ t = Δ θ ω avg = 3 . 4 rev 29 rad / s · 2 π rad 1 rev = 0 . 736649 s . 003 (part 1 of 2) 10.0 points A wheel starts from rest and rotates with constant angular acceleration to an angular speed of 18 rad / s in 3 . 33 s. Find the magnitude of the angular acceler- ation of the wheel. Correct answer: 5 . 40541 rad / s 2 . Explanation: Let : Δ ω = 18 rad / s and Δ t = 3 . 33 s . Angular acceleration is α = Δ w Δ t = 18 rad / s 3 . 33 s = 5 . 40541 rad / s 2 . 004 (part 2 of 2) 10.0 points Find the angle in radians through which it rotates in this time. Correct answer: 29 . 97 rad. Explanation: The angle through which the wheel rotates during this time interval is θ = 1 2 α t 2 = 1 2 (5 . 40541 rad / s 2 ) (3 . 33 s) 2 = 29 . 97 rad . keywords: 005 (part 1 of 2) 10.0 points A grinding wheel, initially at rest, is ro- tated with constant angular acceleration of 6 . 59 rad / s 2 for 8 . 95 s. The wheel is then
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