This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: roofner (bar784) Homework 11 Weathers (22202) 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points A negatively charged particle moving paral- lel to the z-axis enters a magnetic field (point- ing into of the page), as shown in the figure below. z x v y vector B vector B q Figure: is in the x-direction, is in the y-direction, and k is in the z-direction. What is the initial direction of deflection? 1. hatwide F = + k 2. hatwide F = 3. hatwide F = k 4. hatwide F = + correct 5. vector F = 0 ; no deflection 6. hatwide F = + 7. hatwide F = Explanation: Basic Concepts: Magnetic Force on a Charged Particle: vector F = qvectorv vector B Right-hand rule for cross-products. hatwide F vector F bardbl vector F bardbl ; i.e. , a unit vector in the F direc- tion. Solution: The force is vector F = qvectorv vector B . vector B = B ( ) , vectorv = v parenleftBig k parenrightBig , and q < , therefore , vector F = | q | vectorv vector B = | q | v B bracketleftBigparenleftBig k parenrightBig ( ) bracketrightBig = | q | v B (+ ) hatwide F = + . This is the seventh of eight versions of the problem. 002 10.0 points A proton moving at 4 . 9 10 6 m / s through a magnetic field of 6 . 9 T experiences a magnetic force of magnitude 1 . 3 10 12 N. The charge of proton is 1 . 60218 10 19 C and the mass of proton is 1 . 67262 10 27 kg. What is the angle between the protons velocity and the field? Correct answer: 13 . 8858 . Explanation: Let : E = 1 . 3 10 12 N , B = 6 . 9 T , v = 4 . 9 10 6 m / s , q p = 1 . 60218 10 19 C , and m p = 1 . 67262 10 27 kg . The Lorentz force acting on a moving charged particle in a magnetic field is F = q v B sin , where q is the charge, v is the speed, B is the magnetic field. So thus the angle between the velocity and the field is = arcsin bracketleftbigg F q v B bracketrightbigg = arcsin bracketleftbigg (1 . 3 10 12 N) (1 . 60218 10 19 C) 1 (4 . 9 10 6 m / s) (6 . 9 T) bracketrightbigg = 13 . 8858 . roofner (bar784) Homework 11 Weathers (22202) 2 003 (part 1 of 3) 10.0 points The magnetic field over a certain range is...
View Full Document