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Unformatted text preview: roofner (bar784) Homework 15 Weathers (22202) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points A rectangular loop located a distance from a long wire carrying a current is shown in the figure. The wire is parallel to the longest side of the loop. 6 . 75cm 2 . 31 cm 21 . 8cm . 0672A Find the total magnetic flux through the loop. Correct answer: 8 . 62353 10 10 Wb. Explanation: Let : c = 6 . 75 cm , a = 2 . 31 cm , b = 21 . 8 cm , and I = 0 . 0672 A . c a b r dr I From Amp` eres law, the strength of the magnetic field created by the current-carrying wire at a distance r from the wire is (see figure.) B = I 2 r , so the field varies over the loop and is directed perpendicular to the page. Since vector B is parallel to d vector A , the magnetic flux through an area element dA is integraldisplay B dA = integraldisplay I 2 r dA . Note: vector B is not uniform but rather depends on r , so it cannot be removed from the integral. In order to integrate, we express the area element shaded in the figure as dA = b dr . Since r is the only variable that now appears in the integral, we obtain for the magnetic flux B = I 2 b integraldisplay a + c c d r r = I b 2 ln r vextendsingle vextendsingle vextendsingle a + c c = I b 2 ln parenleftbigg a + c c parenrightbigg = (0 . 0672 A)(0 . 218 m) 2 ln parenleftbigg a + c c parenrightbigg = (0 . 0672 A)(0 . 218 m) 2 (0 . 294327) = 8 . 62353 10 10 Wb . 002 10.0 points A solenoid 8 . 7 cm in radius and 88 m in length has 13100 uniformly spaced turns and carries a current of 5 . 8 A. Consider a plane circular surface of radius 3 . 2 cm located at the center of the solenoid with its axis coincident with the axis of the solenoid. What is the magnetic flux through this circular surface?(1 Wb = 1 T m 2 ) Correct answer: 3 . 49041 10 6 Wb....
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