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# HW2 - draw the signals just use/0 for positive pulse no...

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3.13 Answer: 480*500*30=7.2*10 6 R=7.2*10 6 *log 2 32=36 Mbps Answer: 10 log 10 (SNR)=35 dB SNR=3162 C=B log 2 (1+SNR)=4.5*10 6 log 2 (1+3162)=52 Mbps Answer: 10 log 10 (SNR)=3 dB SNR=2 C=B log 2 (1+SNR)=300 log 2 (1+2)=475 bps Answer: a. B=C/(2log 2 M)=9600/(2*4)=1200 Hz b. B=C/(2log 2 M)=9600/(2*8)=600 Hz Find encode the following two bit streams into HBD3 code (assume that the previous I and the previous V pulses are +) You are not required to

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Unformatted text preview: draw the signals, just use +/0/- for positive pulse/ no pulse/negative pulse (e.g., the HDB3 encoding of 1111001 is -+-+00-). (a) 11 0000 1 0000 11 0000 1 (the bits are continuous, the gaps are for clarity) (b) 11 0000 0000 0000 Answer: (a) 11 0000 1 0000 11 0000 1- + - 00 - - +00+ +- 000- + (b) 11 0000 0000 0000-+ -00- +00+ -00-...
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HW2 - draw the signals just use/0 for positive pulse no...

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