Ex_N2ndlaw_rotation

Ex_N2ndlaw_rotation - 2D rigid body kinetics - Newton's 2nd...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
2D rigid body kinetics Newton’s 2nd law for pure rotation Σ τ o = I o α O : fixed pivot (rotation center) Example 1. Two forces are applied as shown to the 10 Kg slender rod that is pivoted at point O , and the rod can rotate in the horizontal plane. Find the angular acceleration of the rod. ( Ans : 80 rad/s 2 ) F 1 = 100 N F 2 = 150 N 36.87° 0.2 m 0.6 m O m , L b M O θ 2. A heavy metal sphere of mass M is mounted on the slender rod that has mass m and length L . The rod is pivoted at one end O and the assembly is released from rest in the position shown. The size of the sphere is negligible compared with the length of the rod. Find the initial angular acceleration of the assembly at the instant it is released. Note : The weight of a rigid body is acting at its center of mass,
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 2

Ex_N2ndlaw_rotation - 2D rigid body kinetics - Newton's 2nd...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online