Ex_N2ndlaw_rotation

# Ex_N2ndlaw_rotation - 2D rigid body kinetics Newton's 2nd...

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2D rigid body kinetics Newton’s 2nd law for pure rotation Σ τ o = I o α O : fixed pivot (rotation center) Example 1. Two forces are applied as shown to the 10 Kg slender rod that is pivoted at point O , and the rod can rotate in the horizontal plane. Find the angular acceleration of the rod. ( Ans : 80 rad/s 2 ) F 1 = 100 N F 2 = 150 N 36.87° 0.2 m 0.6 m O m , L b M O θ 2. A heavy metal sphere of mass M is mounted on the slender rod that has mass m and length L . The rod is pivoted at one end O and the assembly is released from rest in the position shown. The size of the sphere is negligible compared with the length of the rod. Find the initial angular acceleration of the assembly at the instant it is released. Note : The weight of a rigid body is acting at its center of mass,

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## This note was uploaded on 04/06/2008 for the course PHYS 2305 taught by Professor Tschang during the Fall '08 term at Virginia Tech.

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Ex_N2ndlaw_rotation - 2D rigid body kinetics Newton's 2nd...

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