Lecture_6_-_Posit_Slider___Inv_Slider_Cr

Lecture_6_-_Posit_Slider___Inv_Slider_Cr - ME 371 Lecture 6...

This preview shows pages 1–6. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ME 371 Lecture 6 1 ME 371 ME 371 Chapter 4 Chapter 4 Positional Analysis Positional Analysis Slider Slider – – Cranks & Inverted Slider Cranks & Inverted Slider ME 371 Lecture 6 2 Slider – Cranks − For position analysis we will use Vector Loop Approach − We know – Lengths of links 2 & 3 – Offset height – Input angle θ 2 − Calculate – Length of link 1 – Angle θ 3 ME 371 Lecture 6 3 Slider – Cranks Vector loop equation R 2 – R 3 – R 4 – R 1 = 0 Projections: (x and y axis) a cos θ 2 – b¡cos θ 3 – c¡cos θ 4 – d¡=¡0 a sin θ 2 – b¡sin θ 3 – c¡sin θ 4 = 0 here a, b and c are known θ 2 is given θ 4 = 90 ° Solution d = a cos θ 2 – b¡cos θ 3 ME 371 Lecture 6 4 Slider – Cranks Solve for θ 3 using the equation (projection on y axis) a sin θ 2 – b¡sin θ 3 – c¡sin θ 4 = 0 Solution (± 90 of sin-1 ) 1 st configuration 2 nd configuration d = a cos θ 2 – b¡cos θ 3 − = − b c a 2 1 3 sin sin 1 θ θ π θ θ + − − = − b c a 2 1 3 sin sin 2 ME 371 Lecture 6 5 Inverted Slider...
View Full Document

This document was uploaded on 10/27/2011 for the course MECHANICAL 371 at Michigan State University.

Page1 / 20

Lecture_6_-_Posit_Slider___Inv_Slider_Cr - ME 371 Lecture 6...

This preview shows document pages 1 - 6. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online