Homework_Solution__1 - Problem 1.2 1.2 In Prob. 1.1,...

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Unformatted text preview: Problem 1.2 1.2 In Prob. 1.1, knowing that P 2 4O kips, determine the average normal stress at the midsection of (a) rod AB- (b1 rod BC 1.1 Twolsolid cylindrical rods AB and BC are weided together at B and loaded as shown. Determine the magnitude of the force P for which the tensile stress in rod AB is twice the magnitude of the compressive stress in rod BC. M. 2 in- I “P: 40 HP: (+evxsl'an) '- 30 in. ‘—i——¥ 40in. _.i _. 17' 1' 1T 231 __ ‘ 2 P: S A“! ' "A: ‘5,— - 3mg; m 4 p F.— 40 -(Z)CSO§ :— -— 20 UPS _ ‘._e- 20 Min; compression, 3 in. B Li. =_E_ - a—‘ji—‘LT 7 ‘l‘ a 67,3 A“ . 3mg 12. 3k: i 5 L. _E_ T —20 0-85.— -2_B3ksi& 9'“ EL 7, o; 26 Promem 1 5 1.5 A strain gage located at C on the surface of bone AB indicates that the average normal stress in the bone is 3.80 MPa when the bone is subjected to two 1200-N forces as shown. Assuming the cross section of the bone at C to be annular and - knowing that its outer diameter is 25 mm, determine the inner diameter of the home’s lift” cross section at C. A? we -- some, : A= E—(affi as) a 2. A 7. Lip cant-"Lia = Gives“ 1_ (4)0200) adasm we) r mafia >410“ m1 oi: = (ZSXID—ai oil = IH.QS%IOF3\M agrees We Problem 1.7 Each of the four vertical links has an 8 x 36-mm uniform rectangular cross section and each of the four pins has a 16-min diameter. Determine the maximum g value of the average normal stress in the links connecting (a) points B and D, (6) points C and E. EM : of (0,040)}:gn - (0-025+0.mo)(20xi03) = o c a Fan = 32.5 fill-'93 N Link ED is m +ensf'on, g 2 MB: 0: 40.090112? — (0.02.5)(203003) : 0 Fa; 7-" ‘ “2.5mm: M Lin“! CE :5 in comprex‘si'm. (o.ooa)(b,03¢s -.0,o|g ) ll Nari area. 6F One fink ‘For +Bvx$ioin = ‘60X10.6 M2. Far +0.10 Paraflep lpl'n k5) Ant-f: V/O-c Ma Tensije s‘l-ress in fink BD. M a . 3 6 I (an 530 = in A = t XIO 63D: iDi.QMPQ_ 1‘ n07 I i . l E Area. 'For\ one [panic in compressi'om = (0,003)(O-'O3é) = 283 x 10“ m2: Far +m pamflefi fluke, A = 57g #1076 mf F ~12.SVIL53 _ -- '5' — ' b) 6c; = 7?“: = W " 4”" “0 €=F‘”Z"7MP“ 1‘ Problem 1 1 6 1.16 When the force P reached 1600 lb, the wooden specimen shown failed in shear ' along the surface indicated by the dashed line. Determine the average shearing stress along that surface at the time of failure. Area. Iceén sheared: A: (Sm 0.65M 2 L8 lhz 5 Force: Pr 1600 IL Shearing 5+t‘fl-Ss: ’Z’ :3" "A?" =' ’16:? = 889 2’“ 38‘1105? . fi 1.25 A fi-inndiameter steel rod AB is fitted to a round hole near end C of the PrOblem 1 25 wooden member CD. For the loading shown, determine (a) the maximum average normal stress in the wood, (.6) the distance I) for which the average shearing stress is o ‘b 100 psi on the surfaces indicated by the dashed lines, (c) the average bearing stress on i in. ‘50 the wood. (01.) Mag- 3‘-MUM’\ rectifying} srl'wsss {a “Hag wood" Aha = (living) 2 3.375s? P m : 4'44 P5" 6—: 4'44 PSI. fl Dt‘s‘l'kuxce l9 -l:ou'* It: I00 Est. Few slaeaireep aweéc see JD‘Heal pines. rJ ,_ —_.-‘_P._a 1-: P L A 251: i .— 1t5‘ : 7.50 ‘.h' l: : 21:4: " {2303000} b = ZED in. "Q (Q 'Avewqge Lear-"mg sl’ress 0v: +A€ woocp. 7-P— 7—f—T-‘fll =2HDO sf 6; At a“: @403 P 6; '-= 2400 PS; fl Problem“! .28 Dime‘i‘ev A. P 5i» "' a.n: 1.28 Link AB, of width b = 50 mm and thickness r = 6 mm, is used to support the end of a herizontal beam. Knowing that the average normal stress in the link is -140 MPa, and that the average shearing stress in each of the two' pins is 80 MPa, determine (a) the diameter d of the pins, ([7) the average bearing stress in the fink. Poo” AB is {h compressi'am A: wine”. E’5OMM run-1r} trémm L A - (0.050)(o.oo(;3r guano“ m F: «5A : -(—Ir+o><|o“3C300x|O"3 = 42x103N Aprgaz aha, AP _ ? _ 42x103 m . _¢ A?“ “>1: ' some - WW e " ‘-C 69: :41er :2.535*><2c3‘3 c9 F2519 'Mm 2 w, & ‘Rwog 2'? I >13 0” Pa (25. 85x10'3 )(0. Do 6) H 271 fl 6; = M’Pq. ...
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This document was uploaded on 10/28/2011 for the course MECHANICAL 222 at Michigan State University.

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Homework_Solution__1 - Problem 1.2 1.2 In Prob. 1.1,...

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