2-27 chem E homwork anwsers

2-27 chem E homwork anwsers - (c) 17.6% excess NH3 626 mol...

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Wed, Feb 20, 2008 -- Answers for Chapter 4 (Part 2 ) Homework 29. (b) nb1 44.1 mol/hr, no2 = 31.0 mol/hr, nb2 = 24.9 mol/hr, xb2b = 0.035, xb2t = 0.894, xb2x = 0.071, no1 = 55.9 mol/hr, %B in feed that is recovered in overhead from Column 2 = 97.1%, % T in feed that is in bottoms from Column 2 =89.0% 30. (c) 31.1%, x4 = 0.0398 32. (b) 28.6 kg 36. (b) 0.118, 0.278, 9.79 40. (a) 1.25 (b) 175 kmol O2/hr
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Unformatted text preview: (c) 17.6% excess NH3 626 mol 75.1 kg NO 42. 0.749, 19.9% excess, 56.2 mol/s 50. (c) 0.160, fractional yield = 0.875 52. 1532 kg ore 60. (a) 27.0 mol/hr, xN2 = 0.148, xCO = 0.284, xH2 = 0.568, 24.3 mol CH3OH/hr overall conversion = 75.9%, single pass conversion = 14.0% 65. 26.3% 74. 74.8% N2, 3.7% O2, 10.7% CO2, 0.93% CO, 0.087% SO2, 9.8% H2O 77. 28.9% C, 71.1% H , 0.023% S...
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