day04projectilequations

day04projectilequations - | |(8 A\sph4u1\chap2\ → a g =-a...

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a = 0 a , v 2 = v 1 + a t ( 4 29 v av = v 1 + v 2 2 ( 5 29 a g = - 9.80 m / s 2 = - a g = - g RECALL: For constant ----------------------------------------------------------------------------------------- For projectile motion, Horizontally: Vertically: Therefore, (4),(5),(8) | (4) | | (5) | & (6), (7) | (6) | | (7)
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Unformatted text preview: | | (8) A:\sph4u1\chap2\day04projectilequations.doc → a g = -a g or ( -g 29 ) 6 ( 2 1 2 1 t a t v d ∆ + ∆ = ∆ ( 29 7 2 1 2 2 t a t v d ∆-∆ = ∆ ) 8 ( 2 2 1 2 2 d a v v ∆ + =...
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