Day11UniformCircularMotionDerivation

Day11UniformCircularMotionDerivation - Uniform Circular...

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Uniform Circular Motion (i.e. v = constant & R = constant) R R Note: See paragraph 2 on page 101 for a description as to why . θ γ = (similar triangles) ∆ ∆ v v R R = By similar triangles: As ∆∆ tR →→ 0, s ∆ ∆ v v s R or v sv R == . s R A:\sph4u1\chap2\day11uniformcircularmotionderivation.doc
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r a v t sv tR v R because v s t c == = = . . 2 Therefore, r a v R c = 2 1 () Centripetal Acceleration:
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This note was uploaded on 10/27/2011 for the course PHYSICS 1028 taught by Professor C.jones during the Spring '09 term at UWO.

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Day11UniformCircularMotionDerivation - Uniform Circular...

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