day05workek

# day05workek - 1 2 mv 1 2 = E k 2 − E k 1 W = ² E E k = 1...

This preview shows pages 1–2. Sign up to view the full content.

Work Work done by a force on an object = that force x the distance the object moves x cosine of the angle between the force and displacement. = ( [W] = N.m = J (Joule) J = kg m 2 / s 2 W = 0 if ( The earth does no work on the moon as it orbits because ) k W Therefore, (Work-Energy theorem) A:\sph4u1\chap4-5\day05workek.doc ± = 90 o = F A d = m a d = m v 2 2 v 1 2 2 d d W F d cos ± , a s c a l a r c a n b e n e g a t i v e ) F g z ² d = 1 2 mv 2 2

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1 2 mv 1 2 = E k 2 − E k 1 W = ² E E k = 1 2 mv 2 = → ⎯ p 2 2 m or → p = 2 mE k W Kinetic Energy/ Momentum Relationship NOTE: Work & E g = F d ( because ± = o ) a = ( = = = ) F F 0 & a F h if v v ; ² a g v a g 2 1 = m g ² h = ² E g Graphically The area under a F A vs d graph equals work done & also the energy change....
View Full Document

## This note was uploaded on 10/27/2011 for the course PHYSICS 1028 taught by Professor C.jones during the Spring '09 term at UWO.

### Page1 / 2

day05workek - 1 2 mv 1 2 = E k 2 − E k 1 W = ² E E k = 1...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online