T04Example

T04Example - Example 1: (From 2.33, Introduction to...

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Example 1: (From 2.33, Introduction to Electrical Engineering by Irwin) Computer V o in the network in Fig. 1 Answers to Example 1: 36V 48V 6 4 4 8 V o + - Fig. 1 6 6A 48V 4 4 8 V o + - 6A 4 8 V o + - 12A 4 6 4 8 V o + - 6A 2.4 14.4V 4 8 V o + - 2.4 8V 8 4 2.4 8 14.4 V o - = + + × - =
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Use Thevenin’s theorem to find V o in the network shown in Fig. 2 Answers to Example 2: We want to find the V o for the 3 resistor, so we treat the 3 resistor as the load. Let’s use another method to find the Thevenin’s equivalent. We short the voltage sources to find the R TH After short-circuiting all the voltage source and treat 3 as load, we get Convert the Thevenin’s equivalent of the 2 sides of Fig 3 to Norton equivalent 18V 3 3 26 V 3 4 o = + × = 24V 4 2 + - V o 12V 6V 3 Fig. 2 4 2 R TH R TH = 2 // 4 = 3 4 12A 3A
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This note was uploaded on 10/28/2011 for the course ELEC 101 taught by Professor Chan during the Spring '09 term at HKUST.

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T04Example - Example 1: (From 2.33, Introduction to...

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