Constant acceleration motion 020022122()atxxtatax xυυυ=+=+ +−Constant velocity motion 00x==+Example 1. A particle is moving along a straight line with constant acceleration. Measured from a chosen reference frame, the particle‘s position is +2 m at t= 0, and it is at the origin when t= 10 s. If the particle is observed to change its direction of motion at t= 6 s, find the acceleration. Ans: 0.2 m/s22. A man running at a speed of 2 m/s starts to accelerate at t= 0 with a constant acceleration of 0.4 m/s2for 10 s. He maintains his top speed for 5 minutes and then slows down with a constant deceleration. If the man runs a total distance of 1900 m from t= 0 to the time he stops, find his deceleration.
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This note was uploaded on 04/06/2008 for the course PHYS 2305 taught by Professor Tschang during the Fall '08 term at Virginia Tech.