pp15 - PHYSICS A World View Tuesday 8 March 2005 READ Ch...

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PHYSICS: A World View Tuesday, 8 March 2005 READ Ch 7 (pp 131-132); PS 7: 4-6 PRAC Ch 7: Q 1, 5, 15, 21, 23; E 7, 11; P 5 HW #15 Ch 7: Q 4, 12, 26; E 10 Th 10 Mar

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Remember: Quiz on Thursday Covers Chapters 5, 6, and 7
30 m/s 30 m/s 1200 kg 1200 kg What is the total kinetic energy of the system?

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is: 1 2 3 33 33 33 1. zero 2. 36,000 J 3. 1,080,000 J 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200
30 m/s 30 m/s 1200 kg 1200 kg What is the total kinetic energy of the system? KE system = KE left + KE right KE system = 1/2 m l v l 2 + 1/2 m r v r 2 KE system = 1/2 (1200)(+30) 2 + 1/2 (1200)(-30) 2 KE system = 540,000 J + 540,000 J = 1,080,000 J

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30 m/s 30 m/s 1200 kg 1200 kg What is the total momentum of the system? p system = p left + p right p system = m l v l + m r v r p system = (1200)(+30) + (1200)(-30) p system = 36,000 kg m/s + (-36,000 kg m/s) = 0 +x
30 m/s 30 m/s 1200 kg 1200 kg The momentum of the system can’t change so what’s got to happen? p system = p left + p right p system = m l v l + m r v r p system = (1200)(+30) + (1200)(-30) p system = 36,000 kg m/s + (-36,000 kg m/s) = 0 +x

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30 m/s 30 m/s 1200 kg 1200 kg The momentum of the system can’t change so what’s got to happen?
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pp15 - PHYSICS A World View Tuesday 8 March 2005 READ Ch...

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