Unformatted text preview: The center of every circular satellite orbit must be at the center of Earth because the gravitational force points toward Earth’s center. The gravitational force provides the centripetal force necessary for circular motion and the centripetal force for uniform circular motion always points toward the center of the circle. Exercise 12. We can do this problem two ways. We know that the force of gravity decreases as the square of the distance between the satellite and the center of Earth. Therefore, ( 29 ( 29 2 2 2 2 6.6 1 600 kg 10 m/s 138 N 6.6 old E new old new E r R F F mg r R = = ÷ ÷ = = ÷ Note that this is quite a bit smaller than the satellite’s weight of 5500 N on the ground. We can also solve this problem using the law of universal gravitation. ( 29 ( 29 ( 29 ( 29 1 2 2 2 24 2 11 2 2 6 6.6 600 kg 5.98 10 kg m 6.67 10 N 135 N kg 6.6 6.37 10 E E m m mM F G G r R= = × = × × = ÷ × ×...
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This document was uploaded on 10/29/2011 for the course PHSX 103 at MSU Bozeman.
 Fall '02
 GregoryFrancis

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